Alphabet / Letter Series – Hard Level Questions – UGC NET Paper 1

Q1): In the series C, E, H, M, T, ? what will be the next letter?
A) D
B) E
C) F
D) G

Answer: B) E
Explanation: Use A1–Z26 positions: C=3, E=5, H=8, M=13, T=20. The jumps are +2, +3, +5, +7 (consecutive prime numbers). The next prime jump is +11. So, T(20) + 11 = 31. Since 31 βˆ’ 26 = 5, position 5 is E.


Q2): In the series Z, V, Q, K, D, ? what will be the next letter?
A) U
B) V
C) W
D) X

Answer: B) V
Explanation: Convert to positions: Z=26, V=22, Q=17, K=11, D=4. The pattern is subtracting increasing numbers: 26β†’22 (βˆ’4), 22β†’17 (βˆ’5), 17β†’11 (βˆ’6), 11β†’4 (βˆ’7). Next subtract βˆ’8: 4 βˆ’ 8 = βˆ’4. Add 26 to wrap: βˆ’4 + 26 = 22, which is V.


Q3): In the series A, C, F, J, O, ? what will be the next letter?
A) T
B) U
C) V
D) W

Answer: B) U
Explanation: Positions: A=1, C=3, F=6, J=10, O=15. The jumps are +2, +3, +4, +5. Next jump is +6. So, O(15) + 6 = 21, which is U.


Q4): In the series D, J, I, O, N, T, ? what will be the next letter?
A) R
B) S
C) U
D) V

Answer: B) S
Explanation: Positions: D=4. Apply alternating pattern +6, βˆ’1 repeatedly:
D(4) + 6 = J(10)
J(10) βˆ’ 1 = I(9)
I(9) + 6 = O(15)
O(15) βˆ’ 1 = N(14)
N(14) + 6 = T(20)
T(20) βˆ’ 1 = S(19).


Q5): Find the missing letter in the series M, Q, X, H, __, K.
A) T
B) U
C) V
D) W

Answer: B) U
Explanation: Positions: M=13. The jumps increase by +3 each time: +4, +7, +10, +13, +16.
M(13)+4=Q(17)
Q(17)+7=X(24)
X(24)+10=34 β†’ 34βˆ’26=8 = H
H(8)+13=21 = U
U(21)+16=37 β†’ 37βˆ’26=11 = K
So the missing letter is U.


Q6): In the series BD, EG, HK, LO, ? what will be the next pair?
A) PS
B) PT
C) QT
D) PU

Answer: B) PT
Explanation: Treat each letter separately using positions.
First letters: B=2, E=5, H=8, L=12. Jumps are +3, +3, +4, so repeat +4 next: 12+4=16 β†’ P.
Within pairs, the gap between letters is: BD (2β†’4 gap 2), EG (5β†’7 gap 2), HK (8β†’11 gap 3), LO (12β†’15 gap 3). Next gap should be 4. So P(16)+4=20 β†’ T. Therefore the next pair is PT.


Q7): In the series A, D, I, P, Y, ? what will be the next letter?
A) H
B) I
C) J
D) K

Answer: C) J
Explanation: Positions: A=1, D=4, I=9, P=16, Y=25. These are perfect squares: 1Β², 2Β², 3Β², 4Β², 5Β². Next is 6Β² = 36. Since 36βˆ’26=10, position 10 is J.


Q8): In the series B, E, K, T, F, ? what will be the next letter?
A) S
B) T
C) U
D) V

Answer: C) U
Explanation: Positions: B=2. The jumps increase by 3 each time: +3, +6, +9, +12, +15.
B(2)+3=E(5)
E(5)+6=K(11)
K(11)+9=T(20)
T(20)+12=32 β†’ 32βˆ’26=6 = F
F(6)+15=21 = U.


Q9): In the series R, U, P, T, M, ? what will be the next letter?
A) H
B) I
C) J
D) K

Answer: B) I
Explanation: Positions: R=18. The pattern alternates forward and backward with increasing odd numbers:
R(18) +3 = U(21)
U(21) βˆ’5 = P(16)
P(16) +4 = T(20)
T(20) βˆ’7 = M(13)
Next is +5, then βˆ’9 pattern; here from M(13) apply +5 to get R(18), then apply the next backward βˆ’9 for the next term: R(18) βˆ’ 9 = 9 β†’ I.


Q10): In the series A D H, C G L, F K Q, J P W, ? what will be the next group?
A) N U C
B) O V D
C) O U D
D) P V E

Answer: B) O V D
Explanation: Consider each column separately (positions).
First letters: A=1, C=3, F=6, J=10. Jumps are +2, +3, +4. Next jump is +5 β†’ 10+5=15 β†’ O.
Second letters: D=4, G=7, K=11, P=16. Jumps are +3, +4, +5. Next jump is +6 β†’ 16+6=22 β†’ V.
Third letters: H=8, L=12, Q=17, W=23. Jumps are +4, +5, +6. Next jump is +7 β†’ 23+7=30 β†’ 30βˆ’26=4 β†’ D.
So the next group is O V D.


Q11): Find the missing letter in the series L, H, M, I, O, K, R, __, U.
A) L
B) M
C) N
D) O

Answer: C) N
Explanation: Look at the series in pairs: (L, H), (M, I), (O, K), (R, __), (U is the next start).
In each pair, the second letter is 4 steps behind the first:
L(12) βˆ’ 4 = H(8)
M(13) βˆ’ 4 = I(9)
O(15) βˆ’ 4 = K(11)
So, R(18) βˆ’ 4 = 14 β†’ N.


Q12): In the series B, F, K, R, X one letter is wrong. Which one?
A) F
B) K
C) R
D) X

Answer: C) R
Explanation: Check the intended increasing jumps: B(2)β†’F(6) is +4, F(6)β†’K(11) is +5. Next should be +6, so 11+6=17 which is Q, not R(18). After that, the next jump +7 gives 17+7=24 = X, which matches X. So R is the wrong term (it should be Q).


Q13): In the series A, Y, D, V, H, R, ? what will be the next letter?
A) L
B) M
C) N
D) O

Answer: B) M
Explanation: Split into two alternating series.
Odd positions: A(1), D(4), H(8). Jumps are +3, +4, so next jump is +5 β†’ 8+5=13 β†’ M.
Even positions: Y(25), V(22), R(18). Jumps are βˆ’3, βˆ’4, so next would be βˆ’5 β†’ 18βˆ’5=13 β†’ M.
Both confirm the next letter is M.


Q14): In the series Z, A, X, D, U, H, ? what will be the next letter?
A) Q
B) R
C) S
D) T

Answer: A) Q
Explanation: Split into two alternating series.
Odd positions: Z(26), X(24), U(21). These move backward by βˆ’2, βˆ’3. Next is βˆ’4 β†’ 21βˆ’4=17 β†’ Q.
Even positions: A(1), D(4), H(8) move forward by +3, +4 (next would be +5), but the question asks the next term (odd position), so we take Q.


Q15): In the pair series AZ, CX, FU, JQ, OL, ? what will be the next pair?
A) TF
B) UF
C) UG
D) VF

Answer: B) UF
Explanation: Check first letters: A(1), C(3), F(6), J(10), O(15). The jumps are +2, +3, +4, +5. Next jump is +6 β†’ 15+6=21 β†’ U.
Check second letters: Z(26), X(24), U(21), Q(17), L(12). The backward jumps are βˆ’2, βˆ’3, βˆ’4, βˆ’5. Next is βˆ’6 β†’ 12βˆ’6=6 β†’ F.
So the next pair is UF.


Q16): In the series B, E, J, Q, Z, ? what will be the next letter?
A) J
B) K
C) L
D) M

Answer: B) K
Explanation: Positions: B=2, E=5, J=10, Q=17, Z=26. These follow nΒ² + 1:
1Β²+1=2 (B)
2Β²+1=5 (E)
3Β²+1=10 (J)
4Β²+1=17 (Q)
5Β²+1=26 (Z)
Next is 6Β²+1=37. Wrap: 37βˆ’26=11 β†’ K.


Q17): In the series M, R, P, V, S, Z, ? what will be the next letter?
A) U
B) V
C) W
D) X

Answer: B) V
Explanation: Use alternating operations with increasing numbers:
M(13) +5 = R(18)
R(18) βˆ’2 = P(16)
P(16) +6 = V(22)
V(22) βˆ’3 = S(19)
S(19) +7 = Z(26)
Next is βˆ’4: Z(26) βˆ’ 4 = 22 β†’ V.


Q18): In the series BE, EI, IN, NT, ? what will be the next term?
A) TA
B) TB
C) UA
D) UB

Answer: A) TA
Explanation: Notice the chain rule: the first letter of each term is the second letter of the previous term.
BE β†’ next starts with E β†’ EI
EI β†’ next starts with I β†’ IN
IN β†’ next starts with N β†’ NT
So next must start with T. Now look at second letters: E(5), I(9), N(14), T(20). The jumps are +4, +5, +6. Next jump is +7 β†’ 20+7=27 β†’ 27βˆ’26=1 β†’ A.
So the next term is TA.


Q19): In the series BGL, CJO, DMR, EPU, FSW one term is wrong. Which one?
A) BGL
B) CJO
C) EPU
D) FSW

Answer: D) FSW
Explanation: Check letter-by-letter pattern across terms.
First letters: B, C, D, E, F are +1 each time (correct).
Second letters: G(7), J(10), M(13), P(16), S(19) are +3 each time (correct).
Third letters should also be +3: L(12) β†’ O(15) β†’ R(18) β†’ U(21) β†’ next should be X(24).
But the last term has W(23), not X(24). So FSW is wrong (it should be FSX).


Q20): In the series A, Z, C, X, F, U, J, Q, ? what will be the next letter?
A) M
B) N
C) O
D) P

Answer: C) O
Explanation: Split into two alternating series.
Odd positions: A(1), C(3), F(6), J(10). The jumps are +2, +3, +4, so next is +5 β†’ 10+5=15 β†’ O.
Even positions: Z(26), X(24), U(21), Q(17) follow βˆ’2, βˆ’3, βˆ’4 (next would be βˆ’5), but the required next term is an odd position, so the answer is O.

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