UGC NET Questions (Paper – 1)

Statements A, B and C correctly describe major categories of computer software, while statement D is incorrect. System software does manage hardware and provide a base for other programs, application software does handle specific user tasks, and utilities support maintenance and optimisation. Firmware, however, is typically stored in non-volatile memory on hardware devices and not always on removable media. Therefore, the combination that includes A, B and C but excludes D is the only correct answer.

Option A:
Option A includes statements A, B and C and omits D, so it contains exactly the true statements. It recognises the distinct roles of system, application and utility software in a computer system. Because it does not include the false claim about firmware storage, this option accurately represents the set of correct statements.

Option B:
Option B combines A and D only, which makes the set both incomplete and partly wrong. While statement A is true, statement D wrongly suggests that firmware is always stored only on removable media. It also ignores statements B and C, which are correct, so this option cannot represent the full set of correct statements.

Option C:
Option C groups B, C and D together, mixing true and false information. Statements B and C are correct descriptions of application and utility software, but statement D is incorrect about firmware. By excluding statement A, which is also true, and including a false statement, this option cannot be accepted as correct.

Option D:
Option D includes all four statements, so it brings in the incorrect statement D along with the true ones. Because a correct answer must contain only true statements, including D makes this option invalid. Even though A, B and C are correct, the presence of the false statement prevents this combination from being the right answer.

MOOCs leverage ICT to reach thousands of learners simultaneously across geographical boundaries. They typically host video lectures, readings, quizzes and discussion forums on web platforms. Many MOOCs can be joined freely, with optional certification for a fee. Hence, the defining features include openness, scalability and online delivery, which this option captures.

Option A:
A small face-to-face class does not exploit the massiveness or openness that characterise MOOCs. While effective pedagogy is possible, it is not MOOC-based.

Option B:
Printed self-study packs rely on traditional distance education methods without interactive ICT support. They lack the dynamic, web-based features typical of MOOCs.

Option C:
This option correctly highlights openness to large numbers and the central role of the Internet in delivering content and assessing learning. It reflects how platforms like SWAYAM and Coursera operate.

Option D:
Closed in-house training may use online tools but is not open or massive; access is limited by organisational boundaries. Therefore, it is not a MOOC.

Each hexadecimal digit represents exactly 4 binary bits because base 16 equals 2⁴. To encode a 20-bit binary number, we divide 20 by 4 and obtain 5 hex digits. No fewer digits can cover 20 bits, while exactly 5 hex digits provide 5×4 = 20 bits of capacity. Therefore, the minimum number of hexadecimal digits required is 5, so option D is correct.

Option A:
Option A, 4 hex digits, cover only 16 bits, so they are insufficient for 20 bits.

Option B:
Option B, 6 hex digits, cover 24 bits; this is not minimum.

Option C:
Option C, 8 hex digits, cover 32 bits; far from minimum.

Option D:
Option D correctly matches 20 bits to 5 hex digits using 4 bits per hex digit.

Random Access Memory (RAM) is a working area that holds data and instructions currently being processed by the CPU. When power is turned off, its contents are lost, which is why it is called volatile. Read Only Memory (ROM) retains its contents even without power and usually stores firmware like the BIOS that helps start the system. This division of roles is fundamental to understanding ICT hardware.

Option A:
This option incorrectly suggests that neither kind of memory is volatile or changeable. In reality, RAM is volatile and ROM is often programmed at manufacture or through special procedures. The statement fails to capture the essential difference between them.

Option B:
This option mistakenly reverses volatility properties, claiming that RAM retains data without power and ROM does not. Standard computer design is exactly the opposite; ROM is used precisely because it remains stable when the system is off.

Option C:
This option correctly distinguishes temporary working memory from permanent firmware storage. It explains why the system needs both types to operate efficiently and reliably. RAM supports fast processing, while ROM ensures that basic instructions are always available for booting.

Option D:
Suggesting that a computer can start without any RAM or ROM overlooks the fact that instructions and data must be stored somewhere for the CPU to execute them. At minimum, some form of non-volatile memory is required to provide boot code, and volatile memory is needed for normal operation.

Multimedia combines several types of content to create richer learning experiences. Learners may read text, listen to narration, watch animations and interact with diagrams in a single module, which can support different learning styles and increase engagement.

Option A:
Printed text alone represents a single medium and does not exploit the audio or visual capabilities of ICT, so it does not satisfy the notion of multimedia.

Option B:
This option correctly states that more than one medium is used together in a coordinated way, matching common educational tools such as interactive tutorials and video-enriched presentations.

Option C:
A single static picture is just one medium and offers limited interaction; it lacks the combined sensory elements associated with multimedia learning.

Option D:
Handwritten notes on a blackboard are traditional, non-digital teaching aids and do not represent multi-modal digital content in the ICT sense.

To convert binary to hexadecimal, we group the binary digits into sets of four from right to left and convert each group to its hex digit. The binary 110101110010₂ groups as 11 0101 1100 10, which we pad on the left to 0011 0101 1100 10; correctly grouping from right gives 1101 0111 0010. These nibbles correspond to D,7,2 respectively, forming D72₁₆. Therefore, D72₁₆ is the correct hexadecimal representation of 110101110010₂.

Option A:
Option A correctly interprets 1101₂ as D, 0111₂ as 7, and 0010₂ as 2, giving D72₁₆. The grouping into nibbles and mapping into hexadecimal digits follows the standard binary–hex conversion rule. Hence, this option accurately captures the value of the given binary number in base 16.

Option B:
Option B, D62₁₆, implies the middle nibble is 0110₂ instead of 0111₂, which changes the value. This would correspond to a different binary pattern than 110101110010₂. Therefore, D62₁₆ does not match the given binary sequence and is incorrect.

Option C:
Option C, D7A₁₆, takes the last nibble as 1010₂ (A) rather than 0010₂ (2), implying different trailing bits. This would require the binary number to end in 1010, not 0010 as provided. Thus, D7A₁₆ is inconsistent with the original binary digits.

Option D:
Option D, C72₁₆, implies the first nibble is 1100₂ (C) instead of 1101₂ (D), which changes the most significant bits. This modifies the overall magnitude of the number and no longer matches 110101110010₂. Hence, C72₁₆ is not the correct conversion of the given binary number.

A base-2 system uses two symbols, typically 0 and 1, to represent numbers. This system is universally known as the binary number system. It forms the foundation of digital electronics and computer logic. Therefore, the correct alternative name for base 2 is binary.

Option A:
Option A is correct because "bi" signifies two, matching the two symbols used in the system. All computations in digital computers are carried out using this binary representation.

Option B:
Option B, octal, refers to base 8 and uses eight symbols from 0 to 7. It does not describe a base-2 system.

Option C:
Option C, decimal, describes base 10 and uses ten symbols from 0 to 9. This is the everyday counting system, not base 2.

Option D:
Option D, hexadecimal, refers to base 16 which uses sixteen symbols, including letters A–F. It is not equivalent to base 2, although it relates to binary through groups of four bits.

Statements A, B, C, E and F describe core features and practices of educational wikis, whereas D is false. Wikis enable collaborative editing with tracked versions and support project documentation and shared understanding. Guidelines and discussion pages further help maintain quality and resolve disagreements. The claim that instructors can never moderate or revert content is incorrect, so D must be omitted.

Option A:
Option A is incorrect because it omits F and therefore ignores the role of discussion pages in supporting collaboration. While A, B, C and E are correct, leaving out F removes an important communicative feature of many wiki platforms. This makes the option incomplete.

Option B:
Option B is correct because it brings together all the true statements and excludes D. It highlights collaborative editing, version control, group knowledge-building, guidelines and discussion channels as key aspects of educational wikis. Thus it best matches the full set of correct statements.

Option C:
Option C is incorrect because it omits A, which clearly identifies wikis as shared editable spaces. Without A, the collaborative nature of wikis is not fully captured. Even though B, C, E and F are true, leaving out A makes the combination incomplete.

Option D:
Option D is incorrect because it excludes B and so fails to acknowledge revision history as a core feature. While A, C, E and F are true, tracking of versions is also essential, and its omission means the set is not fully correct.

Technology enhanced learning refers to the thoughtful integration of ICT resources into pedagogy to support deeper understanding and engagement. It does not mean using gadgets for their own sake but aligning tools with learning objectives. Examples include simulations, interactive quizzes and educational videos that make concepts more accessible. Therefore the purposeful improvement described in the stem fits technology enhanced learning.

Option A:
Option A, digital divide, focuses on unequal access to technology rather than on using tools to enhance learning. It represents a socio-economic problem rather than an instructional strategy.

Option B:
Option B, computer repair, is a technical maintenance activity and has no inherent educational dimension, so it does not capture the teaching–learning focus of the question.

Option C:
Option C is correct because the phrase explicitly emphasises enhancement of the learning process by means of technology. It highlights added pedagogical value such as improved feedback, collaboration and visualisation.

Option D:
Option D, distance certification, refers to awarding degrees or certificates through distance education programmes and is only one possible outcome, not a general strategy for classroom improvement.

Statements A, B and D correctly identify key features of robust online examination systems, such as automatic scoring, security tools and randomised question papers. Statement C is false because many online systems allow descriptive answers that are later evaluated by human examiners. ICT expands options for both objective and subjective assessment rather than restricting them. Hence, the correct combination is A, B and D only.

Option A:
Option A is correct because it groups the three statements that align with current practice in online testing. It highlights automation, security and randomisation without denying the possibility of human marking. By excluding C, it avoids an overly restrictive view of online exams.

Option B:
Option B is incorrect because it includes only A and D and omits B. Statement B is also correct, since secure browsers and proctoring are widely used to curb malpractice. Leaving out B underplays the importance of security in online examinations.

Option C:
Option C is incorrect because it groups B and C as correct statements. While B is true, C is false because subjective questions can be collected online and marked manually. Including C makes the combination invalid.

Option D:
Option D is incorrect because it treats all four statements as correct, thereby accepting C. Since C misrepresents the capabilities of online systems, any option containing it cannot be correct.

Activities involving analysis, evaluation and creation are typically classified as higher order thinking in frameworks such as Bloom's taxonomy. ICT tools like spreadsheets, simulation software and programming environments can foster these skills by allowing students to manipulate information and explore scenarios. Therefore, the blank should be filled with higher.

Option A:
Option A, lower, order thinking includes basic recall and understanding, which are less demanding and not the main focus of the complex ICT uses described.

Option B:
Option B is correct because using ICT for data analysis and problem solving aligns with higher order cognitive processes.

Option C:
Option C, mechanical, suggests routine, unreflective behaviour, which contradicts the analytical and creative nature of the tasks mentioned.

Option D:
Option D, rote, learning emphasises memorisation without deep understanding and is not the target of such ICT activities.

Statements A, B and D correctly capture both the opportunities and risks of using social media in education, whereas statement C is false. Social media can support peer interaction and collaborative learning, it can also distract when overused and closed groups can be used for sharing academic information. It is wrong to say that social media can never be used for formal academic communication, as many institutions use it for official updates. Therefore, the combination that includes A, B and D but excludes C is the correct answer.

Option A:
Option A is incorrect because it lists only A and B as correct and omits D. While A and B are true, D also accurately describes how closed groups or channels can support academic communication. Leaving out a true statement means this option is incomplete.

Option B:
Option B is incorrect because it includes only B and D and omits A. Statement A is also valid, highlighting the collaborative learning potential of social media. Since one correct statement is missing, this combination does not represent the full set of correct statements.

Option C:
Option C is correct because it groups A, B and D together and excludes the false statement C. It recognises that social media can be both a learning tool and a potential distraction, and that it can be used formally through structured groups. By omitting the claim that social media can never serve formal purposes, this option aligns with current educational practice.

Option D:
Option D is incorrect because it treats all four statements as correct, thereby accepting statement C. The assertion that social media can never be used for formal academic communication is clearly false. Including this incorrect statement invalidates the combination.

Bitmap graphics represent images as grids of individual pixels, each with its own colour value. Common formats like JPEG and PNG use this approach and are widely used for photographs. Bitmap images may lose quality if scaled excessively. Thus, the type of graphic described is bitmap.

Option A:
Option A is correct because bitmap, or raster, graphics are defined by pixel arrays and match formats like JPEG and PNG.

Option B:
Option B, vector, graphics are composed of mathematical paths and shapes and scale without loss of quality, which differs from pixel based images.

Option C:
Option C, 3D, graphics involve three dimensional models and rendering, not simple two dimensional pixel arrays.

Option D:
Option D, holographic, imagery refers to three dimensional representations created through interference patterns and is not the basic format for digital photos.

In any positional number system of radix r, the permissible digits range from 0 to r−1. If a numeral includes the digit 3, then the base must be at least 4, because in base 3 the highest digit allowed is 2. Therefore, the smallest base that can legally contain the digits 0, 1, 2 and 3 is base 4.

Option A:
Option A recognises that the presence of digit 3 forces r−1 ≥ 3, so r ≥ 4. Among the given options, base 4 is the minimal base satisfying this inequality. Thus, it is the smallest valid radix for such numerals.

Option B:
Option B, base 3, can only use digits 0, 1, and 2, since 3 itself is not a valid digit in radix 3. Hence any numeral containing the digit 3 would be invalid in base 3, making this option incorrect.

Option C:
Option C, base 5, is a permissible base for digits 0–3, but it is not the smallest acceptable base. It satisfies r ≥ 4, yet the question specifically asks for the smallest radix, so base 4 is preferred.

Option D:
Option D, base 2, allows only the digits 0 and 1. It cannot represent numerals that contain the digits 2 or 3. Therefore, it is clearly too small to accommodate the given digit set.

Dividing 125 by 16 gives a quotient of 7 and a remainder of 13. In hexadecimal, 13 is represented by D. Therefore, 125 in decimal is written as 7D₁₆. This reflects 7×16 + 13 = 112 + 13 = 125.

Option A:
Option A, 7C₁₆, represents 7×16 + 12 = 124, which is one less than 125. The remainder is too small.

Option B:
Option B is correct because 7×16 = 112 and adding the remainder 13, mapped to D, gives 125. This matches the standard hex conversion process.

Option C:
Option C, 7E₁₆, equals 7×16 + 14 = 126, one more than 125. It overshoots the required value.

Option D:
Option D, 7F₁₆, corresponds to 7×16 + 15 = 127, which is even further from 125.