The equation (x β 3)(x + 5) = 0 is satisfied when either factor is zero. Setting x β 3 = 0 gives x = 3, and setting x + 5 = 0 gives x = β5. The sum of the roots is therefore 3 + (β5) = β2. This also agrees with the general property that for xΒ² + bx + c = 0, the sum of the roots is βb, which is consistent if the equation is expanded.
Option A:
Option A correctly adds the two root values, 3 and β5, to obtain β2. It captures the essence of the relationship between factorized form and the numerical roots.
Option B:
Option B, 2, would arise if one mistakenly subtracted β5 from 3 or ignored the sign of one root, but that does not reflect the actual arithmetic.
Option C:
Option C, β8, is the product of the roots, not their sum. It reflects a different relation in quadratics and confuses two separate concepts.
Option D:
Option D, 8, would require both roots to be positive or both negative with different magnitudes, which is not the case for this factorization.
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