Palindromic three letter mirror series – UGC NET Question

Each group is a three letter palindrome where the first and last letters are the same and increase in order A, B, C, D. The middle letters move backwards from the end of the alphabet in the order Z, Y, X, W. The next outer letter should be E and the next middle letter in this backward sequence should be V. Thus EVE is the only group that satisfies both movements simultaneously.

Option A:
Option A, EUE, uses E correctly as the outer letter but chooses U instead of V for the middle position. The middle letters have been stepping down one letter at a time from Z, and U would skip V in that sequence. Because it breaks this simple reverse progression, EUE cannot be the right continuation.

Option B:
Option B is correct because it combines E as the next outer letter and V as the next middle letter after W. It preserves the palindromic structure and keeps the two opposing movements of outer letters forward and inner letters backward perfectly intact. This strict adherence to the observed pattern makes EVE the logical next term.

Option C:
Option C, EVF, is not a palindrome at all since the first and last letters do not match. The series clearly uses groups where the outer letters are identical. By breaking this defining structural feature, EVF fails to follow the pattern of the series.

Option D:
Option D, EWE, keeps the palindromic structure but repeats W as the middle letter instead of moving to V. This freezes the backward movement of the central letters, which has been consistent so far. Therefore EWE does not continue the pattern correctly.