Odd Number in a Group – UGC NET Question

A number is divisible by 6 if and only if it is divisible by both 2 and 3. The numbers 12, 18 and 24 are all even and their digit sums are divisible by 3, so each is divisible by 6. The number 35 is not even and its digit sum is 3 + 5 = 8, which is not divisible by 3. Therefore, 35 is not divisible by 6 and stands out from the rest.

Option A:
Option A, 12, is divisible by 2 and by 3, which means it is divisible by 6 and thus similar to 18 and 24 in this property. It cannot be regarded as the odd one when considering divisibility by 6.

Option B:
Option B, 18, also satisfies the test for divisibility by 6, being divisible by 2 and 3, so it remains within the main group.

Option C:
Option C, 24, is divisible by 2 and 3 as well, so it again fits the common pattern shared by the first three numbers in the list.

Option D:
Option D, 35, fails to meet either of the conditions for divisibility by 6, because it is not even and the sum of its digits is not divisible by 3. This makes it uniquely different in the given set.