UGC NET Questions (Paper – 1)

A number is divisible by 6 if and only if it is divisible by both 2 and 3. The numbers 12, 18 and 24 are all even and their digit sums are divisible by 3, so each is divisible by 6. The number 35 is not even and its digit sum is 3 + 5 = 8, which is not divisible by 3. Therefore, 35 is not divisible by 6 and stands out from the rest.

Option A:
Option A, 12, is divisible by 2 and by 3, which means it is divisible by 6 and thus similar to 18 and 24 in this property. It cannot be regarded as the odd one when considering divisibility by 6.

Option B:
Option B, 18, also satisfies the test for divisibility by 6, being divisible by 2 and 3, so it remains within the main group.

Option C:
Option C, 24, is divisible by 2 and 3 as well, so it again fits the common pattern shared by the first three numbers in the list.

Option D:
Option D, 35, fails to meet either of the conditions for divisibility by 6, because it is not even and the sum of its digits is not divisible by 3. This makes it uniquely different in the given set.

Statements A and B give correct definitions of union and intersection, D correctly states that the empty set is a subset of every set and E is true because many reasoning problems about groups naturally use set models and sometimes Venn diagrams. Statement C is false since the complement of A in U consists of elements of U that are not in A, not elements that are in both A and U. Therefore, the combination A, B, D and E only is correct.

Option A:
Option A is incomplete because it omits E and so does not mention the common application of set theory to practical reasoning questions in exams. Without E, the conceptual link to aptitude problems is weakened.

Option B:
Option B is also incomplete as it leaves out A and therefore fails to give the basic description of union, which is central to understanding combined categories in reasoning questions.

Option C:
Option C is wrong because it includes C, which misdescribes complement, and omits E, ignoring the modelling role of sets. Including a false statement invalidates the option.

Option D:
Option D is correct as it keeps all true statements while excluding C, the incorrect account of complement. It aligns with the formal set-theoretic framework used for UGC NET reasoning items.