Letter series D G J M P – UGC NET Question

The positions of the letters are D(4), G(7), J(10), M(13) and P(16). Each step increases the position by 3 (4→7→10→13→16). Continuing this constant difference, the next position is 16 + 3 = 19, which corresponds to S. Therefore S is the only letter that preserves the fixed +3 pattern of the series.

Option A:
Option A is correct because S is exactly 3 positions after P in the alphabet. It keeps the same arithmetic progression of positions that has been followed throughout the series. By maintaining this constant increment, S fits perfectly as the next term.

Option B:
Option B, R, is only 2 positions after P(16→18), which breaks the consistent step size of 3. Choosing R would change the underlying rule from a fixed difference to a variable one. Hence R cannot logically continue the established sequence.

Option C:
Option C, T, is 4 positions after P(16→20), overshooting the required increment. This would increase the step size without any prior indication of such change. As the pattern clearly uses equal jumps, T is not a valid continuation.

Option D:
Option D, U, lies 5 positions after P(16→21), producing an even larger jump. This completely disrupts the constant difference structure of the series. Therefore U cannot be accepted as the next term.