Letter series BD FH JL NP – UGC NET Question

For this series, the first letters are B(2), F(6), J(10) and N(14), each increasing by 4. The second letters are D(4), H(8), L(12) and P(16), also increasing by 4. The next first letter is 14 + 4 = 18, which is R, and the next second letter is 16 + 4 = 20, which is T. Thus RT is the pair that continues the uniform +4 progression in both positions.

Option A:
Option A is correct because both letters follow the established pattern of adding four positions. It places R after N and T after P, matching the arithmetic sequence. This preserves the symmetry between the first and second letters in the series.

Option B:
Option B, QS, has Q as the first letter, which is only 2 steps ahead of N, contradicting the +4 rule. Its second letter S is also only 2 steps beyond P. Since both gaps are too small, QS fails to maintain the consistent structure.

Option C:
Option C, RU, gives the correct first letter R but moves the second letter to U, which is 5 steps ahead of P. This breaks the equal step requirement for both letters. Because it inflates the second-letter increment, RU cannot be accepted.

Option D:
Option D, ST, advances the first letter to S, which is 5 positions ahead of N. This oversteps the observed increment and loses the alignment with the second letter’s movement. As a result, ST does not match the series rule.