Four-letter sliding series from P – UGC NET Question

Each term is a block of four consecutive letters and the block slides one position to the right in the alphabet. The starting letters P, Q, R and S progress forward by one step in each term. After STUV, the next block should begin with T and include the next three letters U, V and W. Hence TUVW is the unique group that continues the sliding four letter window pattern.

Option A:
Option A, UVWX, is a proper four letter block but its starting letter U is two steps ahead of S rather than one. It corresponds to the block that would come after TUVW, not immediately after STUV. Because the series advances the starting point by only one letter at a time, UVWX cannot be the immediate next term.

Option B:
Option B is correct because TUVW starts with T, the next letter after S, and continues with U, V and W in order. It keeps both the length of the group and the sliding by one letter consistent with all earlier transitions. This perfect match with the sliding window rule makes TUVW the correct continuation.

Option C:
Option C, STUV, simply repeats the last given term instead of moving the starting letter forward. The pattern does not show any repetition or cycling of groups. Using STUV again would freeze the progression, so it cannot be the right answer.

Option D:
Option D, RSTU, moves backward in the sequence to a previous block. The series clearly moves forward in the alphabet, and there is no indication of reversal. Thus RSTU does not fit as the next term.