To convert binary to octal, we group the binary digits into triples from the right and convert each group to its octal digit. The binary 1110110011β can be written as 001 110 110 011, giving octal digits 1, 6, 6 and 3. This results in the octal number 1663β. Since this corresponds to the same value as the original binary, option D is correct.
Option A:
Option A corresponds to a different octal pattern whose binary form is not 1110110011β. When regrouped into binary, it yields a distinct set of bits and therefore a different decimal value. Thus, it does not match the given binary number.
Option B:
Option B produces a larger octal number which, when converted back to binary and then decimal, exceeds the value of 1110110011β. It involves a higher octal digit in one position, making it inconsistent with the required binary pattern. Hence, it is not correct.
Option C:
Option C differs from the correct option in one of its octal digits, which changes the underlying three-bit group. This leads to a binary value that is not 1110110011β and therefore not equal to the given binary number. Thus, it is an incorrect octal equivalent.
Option D:
Option D correctly groups the binary digits and converts each group to its octal counterpart, yielding 1663β. Its reverse conversion reproduces the original binary number exactly. Therefore, this option represents the accurate octal equivalent of 1110110011β.
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