Binary to octal 1234 relation – UGC NET Question

To convert 10011010010₂ to octal, we group the bits into triples from the right: 010 011 010 010, which corresponds to octal digits 2, 3, 2 and 2. This gives the octal number 2322₈. If we convert 2322₈ back to decimal, we obtain 1234, confirming the correctness of the conversion. Therefore, option A is the correct octal equivalent of the given binary number.

Option A:
Option A correctly groups the binary digits and interprets each triple as an octal digit, reproducing the original binary when reversed. Its decimal value also matches 1234, which confirms that the mapping is accurate.

Option B:
Option B differs in one of the octal digits, changing one three-bit group and leading to a different binary pattern. As a result, the corresponding decimal value is not 1234, so it cannot match the given binary representation.

Option C:
Option C modifies another octal digit relative to the correct answer, so its underlying binary pattern differs in at least one three-bit block. This leads to a decimal value that is higher than 1234 and makes it an incorrect choice.

Option D:
Option D rearranges the octal digits in a way that changes multiple three-bit groups, producing a binary string distinct from 10011010010₂. Therefore, it does not give the correct octal representation of the given binary number.