Binary of decimal 200 – UGC NET Question

200 = 128 + 64 + 8, so bits for 2⁷, 2⁶, and 2³ are 1, giving 11001000₂.

Option A:
Option A matches 128 + 64 + 8 = 200.

Option B:
Option B equals 196 (128 + 64 + 4).

Option C:
Option C equals 212 (128 + 64 + 16 + 4).

Option D:
Option D equals 168 (128 + 32 + 8).