UGC NET Questions (Paper – 1)

The first letters A, B, C and D occupy positions 1, 2, 3 and 4, increasing by 1. The second letters M, L, K and J occupy positions 13, 12, 11 and 10, decreasing by 1. The next first letter should therefore be E (5) and the next second letter should be I (9). Combining them gives EI as the unique pair that continues both directions of movement.

Option A:
Option A is correct because it places E after D in the first-letter sequence and I before J in the second-letter sequence. It maintains the symmetric convergence of the two letters toward the middle of the alphabet. This dual movement is exactly what defines the pattern.

Option B:
Option B, EK, keeps E as the first letter but uses K as the second letter, which should already have been passed in the downward sequence. The second letters must keep moving backward without repeating earlier positions. As K is out of order, EK cannot be the correct continuation.

Option C:
Option C, FH, advances the first letter by two steps from D to F and moves the second letter too far back to H. This breaks the consistent one-step changes in both positions. Because it alters the movement rule, FH is not acceptable.

Option D:
Option D, EL, moves the first letter correctly to E but leaves the second letter at L, which reverses direction from the decreasing trend. Instead of moving to 9, it jumps back to 12, contradicting the pattern. Therefore EL does not fit the sequence.