In propositional logic, the connective โandโ corresponds to conjunction. A conjunction p and q is true only when both component statements p and q are true simultaneously. Here p says the number is even and q says it is divisible by 3. Putting them together with โandโ requires both properties to hold. Thus, the combined statement means that the number must be even and divisible by 3.
Option A:
Option A uses โorโ instead of โand,โ which corresponds to a different connective (disjunction). It allows numbers that are only even or only divisible by 3, and hence does not capture the meaning of โp and q.โ
Option B:
Option B mixes โeitherโ with a negation in a way that is not equivalent to the original conjunction. It introduces โnot divisible by 3,โ which is not part of q.
Option C:
Option C reflects the standard interpretation of a logical conjunction: both conditions must be simultaneously satisfied. It directly translates โp and qโ into ordinary language as โeven and divisible by 3.โ
Option D:
Option D makes both properties false, which would correspond to the negation of p and q, not the conjunction of p and q.
Comment Your Answer
Please login to comment your answer.
Sign In
Sign Up
Answers commented by others
No answers commented yet. Be the first to comment!