UGC NET Questions (Paper – 1)

Statements A, B, C, D and F are correct, whereas E is false. Looking at differences or ratios is a standard strategy, and some series do mix patterns, making B true. Letter positions and trend recognition also guide solution strategies, and regular practice builds both speed and accuracy. E is wrong because series patterns are not fixed in advance and are part of what examinees must discover. Hence A, B, C, D and F only is the correct combination.

Option A:
Option A is incomplete because it omits F, which correctly states the value of practice in mastering series questions. While A, B, C and D describe pattern-finding strategies, they do not mention performance improvement through practice. This omission makes the option less comprehensive than the full set of true statements.

Option B:
Option B is correct because it includes all the strategy-related statements along with the point about practice and excludes E, which mischaracterises the nature of test items. It provides both conceptual guidance and exam-related insight. Therefore this option best matches the intended set of correct statements.

Option C:
Option C is wrong because it includes E, which suggests patterns are announced in advance, and it omits A. Accepting E would undermine the challenge of series questions, and leaving out A removes a key analytic technique. As such, B, C, D, E and F only cannot be the right answer.

Option D:
Option D is incorrect since it contains E and omits B and F. Without B, it ignores the possibility of mixed patterns, and without F it misses the role of practice. Including E’s false claim further weakens the combination. Thus A, C, D, E and F only is not acceptable.

Statements A, B, C and E correctly contrast reasoning with heavy computation and reflect typical strategies for Paper 1, while D and F are false. Reasoning items emphasise structure, form and pattern rather than formula-heavy calculations, and some are embedded in short data contexts. Managing time by prioritising clearer questions is a sensible exam tactic. D exaggerates the role of memorising formulas, and F is wrong because reasoning can appear in short passages or caselets. Thus A, B, C and E only is the correct combination.

Option A:
Option A is incomplete because it leaves out E, which conveys an important practical strategy for handling reasoning sections efficiently. Without E, the advice on how to approach questions under time pressure is missing. Therefore A, B and C only is not fully adequate.

Option B:
Option B is incorrect since it omits B, one of the core statements about the importance of logical form in syllogisms, and includes only A, C and E. Without B, the nature of syllogistic reasoning is under-described, so the option does not reflect all correct statements.

Option C:
Option C is correct as it combines conceptual and strategic points relevant to UGC NET Paper 1 while excluding D and F, which misrepresent the nature of reasoning items. It aligns with how the exam is designed and taught in coaching materials. Hence this is the right answer.

Option D:
Option D is wrong because it accepts F and omits A, treating passage-based reasoning as non-existent and leaving out the central idea that patterns and structures matter. This mixture of omission and error prevents the option from being correct.

The terms are squares of consecutive even numbers: 2² = 4, 4² = 16, 6² = 36 and 8² = 64. The next even number in sequence is 10. Squaring 10 gives 100. Therefore, 100 is the next term that preserves this structure.

Option A:
Option A is 90, which is not a perfect square and cannot be written as k² for an integer k. It breaks the pattern of exact squares. Hence, this option is not suitable.

Option B:
Option B is 96, again not a perfect square of an integer. There is no clear way to match it with the rule based on even squares. Therefore, 96 is not correct.

Option C:
Option C equals 100, which is 10² and follows 2², 4², 6² and 8² naturally. The extended series 4, 16, 36, 64, 100 completes the pattern of consecutive even squares. This makes 100 the valid continuation.

Option D:
Option D is 108, which lies between 10² and 11² but is not itself a square. Since the rule is precisely about squares, 108 cannot be accepted.

Each term after the first is obtained by doubling the previous term and adding 2. We have 1 × 2 + 2 = 4, 4 × 2 + 2 = 10, 10 × 2 + 2 = 22, 22 × 2 + 2 = 46 and 46 × 2 + 2 = 94. Applying the same rule to 94 gives 94 × 2 + 2 = 188 + 2 = 190. This maintains a clear and consistent recursive relationship.

Option A:
Option A gives 186, which does not equal 94 × 2 + 2 and would require reducing or changing the constant term. This is not supported by any previous step. Hence, 186 is not correct.

Option B:
Option B offers 188, corresponding to 94 × 2, but misses the required addition of 2 that appears in every transition. This makes the pattern incomplete. Therefore, 188 cannot be accepted.

Option C:
Option C suggests 192, which adds 4 after doubling 94 and introduces a new constant unobserved earlier. This breaks the precise rule of "+2" at the end. Thus, 192 is not appropriate.

Option D:
Option D yields 190, exactly equal to 94 × 2 + 2, and continues the series under one stable transformation. The sequence 1, 4, 10, 22, 46, 94, 190 remains coherent. Therefore, 190 is the correct next term.

Each term after the first is obtained by doubling the previous term and subtracting 1. We have 3×2−1 = 5, 5×2−1 = 9, 9×2−1 = 17 and 17×2−1 = 33, confirming the rule. Applying it again gives 33×2−1 = 66−1 = 65. Hence, 65 is the correct next term.

Option A:
Option A is 63, which would require subtracting 3 from 33×2, not 1. The series consistently subtracts 1, so altering that constant is unjustified. Therefore, 63 is incorrect.

Option B:
Option B is 64, implying that we simply double 33 and subtract 2. Such a modification has no support from the earlier steps. Thus, 64 cannot match the pattern.

Option C:
Option C equals 65 and follows the rule 33×2−1 exactly. The extended sequence 3, 5, 9, 17, 33, 65 is perfectly consistent with the defined operation. This makes 65 the valid continuation.

Option D:
Option D is 67, which would result from 33×2+1 and introduces addition instead of subtraction. Since all previous transitions subtracted 1, this change breaks the rule. Therefore, 67 is not appropriate.

In this series, each new group is obtained by shifting every letter of the previous group one step forward in the alphabet. ACDF becomes BDEG, then CEFH, then DFGI by this uniform +1 movement in all positions. Applying the same rule once more, D becomes E, F becomes G, G becomes H and I becomes J. Therefore EGHJ is the only group that correctly continues the pattern.

Option A:
Option A is correct because it preserves the exact transformation seen between all consecutive terms. Every letter is increased by one step from the previous group DFGI, giving E, G, H and J in order. This keeps the structure and spacing of the letters unchanged, so EGHJ fits perfectly as the next term.

Option B:
Option B, EGHI, keeps the first three letters correctly but leaves the last letter as I instead of advancing it to J. This breaks the rule that every position must move forward by one step. Because the last letter does not follow the established shift, EGHI cannot be accepted as the next term.

Option C:
Option C, EFGJ, changes the second letter incorrectly to F, which does not come from shifting F in the previous group. It also disturbs the internal spacing between letters, which has been maintained in all earlier terms. Since it fails to apply the uniform +1 movement to every position, EFGJ does not fit the series.

Option D:
Option D, FGHI, looks like a familiar consecutive pattern but is not derived from DFGI by adding one to each letter. It replaces D with F, which is a jump of two positions, and creates a different spacing between letters. As it does not follow the consistent transformation rule, FGHI is not the correct continuation.

Each new group is formed by adding +1 to every letter: CAM→DBN→ECO→FDP. Next is FDP shifted to GEQ.

Option A:
Option A changes the second letter incorrectly and does not apply +1 uniformly.

Option B:
Option B uses D as the middle letter, which is not +1 from D in FDP (it should become E).

Option C:
Option C ends with R, which is +2 from P, not +1.

Option D:
Option D is correct because F→G, D→E, P→Q.

The given series consists of perfect squares of natural numbers. Specifically, 1² = 1, 2² = 4, 3² = 9, 4² = 16 and 5² = 25. The next term should therefore be 6², which is 36. This continues the clear pattern of successive squares.

Option A:
Option A, 30, does not correspond to any perfect square and breaks the pattern of square numbers. It would require a different rule that is not evident in the series.

Option B:
Option B, 32, is also not a perfect square and falls between 25 and 36 without a clear basis from squaring integers.

Option C:
Option C, 35, is again not a perfect square and therefore cannot follow the pattern of 1², 2², 3², 4² and 5².

Option D:
Option D, 36, is 6² and naturally follows 5² = 25 in the sequence of square numbers. It maintains the structure of the series and is therefore the correct next term.

Each term is obtained by doubling the previous term and adding 1. We see 2 × 2 + 1 = 5, 5 × 2 + 1 = 11, 11 × 2 + 1 = 23, 23 × 2 + 1 = 47 and 47 × 2 + 1 = 95. Applying this rule again gives 95 × 2 + 1 = 190 + 1 = 191. This preserves the recursive structure of the series.

Option A:
Option A gives 187, which does not equal 95 × 2 + 1 and would require a different constant or operation. This breaks the "times two plus one" rule seen earlier. Therefore, 187 is not consistent with the pattern.

Option B:
Option B offers 189, which corresponds to adding −1 after doubling 95 or some other ad hoc change. This is not supported by earlier transitions. Hence, 189 cannot be accepted.

Option C:
Option C suggests 190, which is simply 95 × 2 and omits the addition of 1 that is present in every previous step. This makes the rule incomplete and inconsistent. Thus, 190 is not appropriate.

Option D:
Option D yields 191, which exactly matches 95 × 2 + 1 and continues the recursive pattern in a straightforward way. The series remains internally coherent. Therefore, 191 is the correct next term.

The series can be generated using the expression 2n² + 1 for consecutive integers n. For n = 1 to 5 we obtain 2(1)² + 1 = 3, 2(2)² + 1 = 9, 2(3)² + 1 = 19, 2(4)² + 1 = 33 and 2(5)² + 1 = 51. The next integer is 6, so the next term should be 2(6)² + 1. This equals 2 × 36 + 1 = 72 + 1 = 73, which is consistent with the pattern.

Option A:
Option A gives 73, which exactly matches the formula 2n² + 1 when n = 6. The extended sequence 3, 9, 19, 33, 51, 73 is generated smoothly from one algebraic rule. This confirms that 73 is the correct continuation of the number series.

Option B:
Option B suggests 71, which does not satisfy the expression 2n² + 1 for any integer following 5 in this context. Using 71 would break the simple polynomial structure underlying the series. Therefore, 71 cannot be the correct next term.

Option C:
Option C provides 75, which also fails to match 2n² + 1 for the next integer. It introduces an inconsistent jump that is not supported by the existing values. Hence, 75 is not in harmony with the pattern of the sequence.

Option D:
Option D offers 77, which similarly does not correspond to 2n² + 1 for n = 6 or any immediate extension. Including 77 would abandon the clear quadratic rule. Thus, 77 is not the appropriate choice.

Within each group the jumps between letters follow a specific pattern of unequal steps. ACFJ uses one distance between the first pair of letters and a larger one between the next pairs, and the same structure appears in BDGK, CEHL and DFIM. From one group to the next, every letter moves forward by one position in the alphabet, so the columns each form a simple sequence. Shifting every letter in DFIM forward by one gives EGJN, which keeps the same internal spacing while extending each column, so it is the correct next term.

Option A:
Option A, EGIN, starts with the right two letters but then changes the internal differences between the later letters. The progression from G to I to N no longer matches the jumps used inside the earlier groups. Because it distorts the internal pattern, EGIN cannot be the next term in this series.

Option B:
Option B is correct because EGJN is obtained by adding one to each letter of DFIM and at the same time preserves the unequal but consistent gaps between positions. The first letters move from A to D to E in order and the other columns also extend cleanly. This combination of column wise advancement and preserved internal structure shows that EGJN properly continues the sequence.

Option C:
Option C, FHKO, moves the starting letter two steps ahead of D and disrupts the simple one step growth across the first column. It also alters the spacing between inner letters so that they no longer mirror the earlier terms. Hence FHKO does not align with the defined pattern.

Option D:
Option D, EGJO, keeps most letters close but sends the last letter too far ahead, changing the final gap inside the group. This breaks the consistent relation between the third and fourth letters found in ACFJ, BDGK, CEHL and DFIM. Therefore EGJO is not a valid continuation.

Each term in the series can be expressed as n³ + 1 for successive integers n. When n = 1, 2, 3, 4 and 5, we obtain 1³ + 1 = 2, 2³ + 1 = 9, 3³ + 1 = 28, 4³ + 1 = 65 and 5³ + 1 = 126. The next integer is 6, so the next term should be 6³ + 1. This equals 216 + 1 = 217, which perfectly matches the observed rule.

Option A:
Option A gives 217, which fits the formula n³ + 1 when n = 6. Extending the sequence to 2, 9, 28, 65, 126, 217 keeps the entire series under one simple cubic rule. This confirms that 217 is the correct next term.

Option B:
Option B suggests 218, which is one more than 217 and does not correspond to n³ + 1 for any integer in the natural continuation. It breaks the tight relationship between n and the terms. Therefore, 218 cannot be accepted as correct.

Option C:
Option C offers 225, which is a square number (15²) but not of the form n³ + 1 in this context. It introduces a different kind of pattern unrelated to the existing terms. Hence, 225 does not match the logic of the series.

Option D:
Option D provides 230, which likewise fails to satisfy the n³ + 1 relation for any integer following 5 in sequence. Choosing 230 would abandon the clearly established cubic structure. Thus, 230 is not the right answer.

Statements A and B correctly describe arithmetic and geometric series as having constant difference and constant ratio respectively. Statement C is also true because many exam series mix patterns, for example by forming two interleaved sub-sequences. Statement E is correct since checking whether values rise, fall or oscillate helps to guess the right pattern. Statement D is false as some questions deliberately use interleaving or alternating rules. Therefore, the only combination that gathers all true statements and excludes the false one is A, B, C and E only.

Option A:
Option A is incorrect because although A, B and C are all true, the option omits E, which is also a correct and useful principle for analysing series. Since it does not list all the true statements, it cannot be the right answer.

Option B:
Option B is correct because it includes each true statement (A, B, C and E) and excludes D, which wrongly denies the possibility of interleaved or alternating sub-series in exam questions. It therefore matches the complete set of correct statements.

Option C:
Option C is wrong because it includes D, which incorrectly rules out interleaving of sub-series, and at the same time leaves out B, which correctly characterises geometric series. The presence of a false statement and the omission of a true one make this combination invalid.

Option D:
Option D is incorrect because it retains D along with B and E and omits A and C, so it both includes a false restriction about patterns and drops two true statements about arithmetic and mixed series.

The given terms are squares of consecutive integers: 4² = 16, 5² = 25, 6² = 36 and 7² = 49. The next integer is 8, so the next term should be 8². Calculating 8² gives 64. Thus, 64 correctly continues the sequence.

Option A:
Option A matches the pattern because it is 8² and follows directly after 7². The extended list 16, 25, 36, 49, 64 represents squares of 4, 5, 6, 7 and 8. This makes the rule clear and consistent.

Option B:
Option B is 56, not a perfect square of any integer and lying between 7² and 8². It cannot be justified under the consecutive square rule. Hence, it is not correct.

Option C:
Option C is 60, which again is not a perfect square and has no natural connection to the sequence. Including it would break the neat square pattern. Therefore, 60 cannot be accepted.

Option D:
Option D is 72, which also is not a perfect square and sits above 8². This choice does not respect the structure based on exact squares. Thus, it is not appropriate.

The rule states that each letter is replaced by the next letter in the alphabet. For the word NET, N is followed by O, E is followed by F and T is followed by U. Replacing each letter accordingly, N becomes O, E becomes F and T becomes U, giving the code OFU. This maintains the same pattern that was used to convert WORD into XPSE.

Option A:
Option A correctly shifts every letter of NET forward by one position, providing O from N, F from E and U from T. It applies the coding rule consistently to all positions and thus matches the example given.

Option B:
Option B, OEU, shifts only some letters correctly and uses E instead of F for the second position. This breaks the uniform next-letter rule for the middle letter.

Option C:
Option C, MFS, shifts N backwards to M instead of forwards and only partially follows the pattern. It does not consistently apply the specified direction of shift.

Option D:
Option D, NEU, keeps N unchanged, which contradicts the rule that each letter must be replaced by its immediate successor in the alphabet.