Successive terms decrease by 3: 17 β 20 = β3, 14 β 17 = β3 and 11 β 14 = β3. This forms an arithmetic progression with common difference β3. Subtracting 3 from the last term 11 gives 8. Therefore, 8 is the next term in the series.
Option A:
Option A keeps the same step because 11 β 3 = 8, maintaining the constant change of β3. The series 20, 17, 14, 11, 8 stays perfectly regular under this rule. Hence, this option correctly extends the pattern.
Option B:
Option B is 10, which is only 1 less than 11 and would change the difference to β1. That conflicts with the consistent decrease by 3 observed earlier. Therefore, 10 cannot be accepted.
Option C:
Option C is 9, giving a difference of β2 from 11 and again disturbing the established constant difference. The sequence would become irregular at the end. Thus, 9 is not correct.
Option D:
Option D is 7, which is 4 less than 11, producing a difference of β4. This also contradicts the steady difference of β3 that defines the progression. Therefore, 7 is not the right choice.
Comment Your Answer
Please login to comment your answer.
Sign In
Sign Up
Answers commented by others
No answers commented yet. Be the first to comment!