UGC NET Questions (Paper – 1)

Each term decreases by 8: 72 − 80 = −8, 64 − 72 = −8, 56 − 64 = −8 and 48 − 56 = −8. Maintaining this constant difference, we subtract 8 from 48 to get 40. Therefore, 40 is the correct next term in the series.

Option A:
Option A is 42, which is 6 less than 48 and would change the difference to −6. This contradicts the steady −8 observed earlier. Hence, 42 is not correct.

Option B:
Option B is 44, implying a difference of −4 from 48. That halves the magnitude of the step and breaks the pattern of equal decreases. Therefore, 44 cannot be accepted.

Option C:
Option C is 46, giving a difference of −2, which is far from the established −8. It would indicate a slowing decline not supported by earlier terms. Thus, 46 is not suitable.

Option D:
Option D equals 40, obtained by 48 − 8 and preserving the constant step of −8. The extended sequence 80, 72, 64, 56, 48, 40 remains a neat arithmetic progression. This confirms 40 as the correct continuation.

The differences are −5, −8, −11 and −14, which decrease by 3 each time. The next difference should therefore be −17. Adding −17 to the last term 12 gives 12 − 17 = −5. Hence, −5 is the correct next term in the series.

Option A:
Option A uses the new difference −17 and yields −5, keeping the second-level pattern of subtracting 3 from each successive difference. The extended sequence of differences −5, −8, −11, −14, −17 remains consistent. Thus, −5 correctly continues the series.

Option B:
Option B is 0, which would require subtracting 12 from 12, corresponding to a difference of −12. That does not follow the −5, −8, −11, −14 progression. Therefore, 0 is not correct.

Option C:
Option C is 2, which implies a difference of −10 from 12. This value does not arise from continuing the pattern of reducing differences by 3. Hence, 2 cannot be accepted.

Option D:
Option D is 4, yielding a difference of −8, which repeats an earlier step rather than moving further by −3. This breaks the steadily changing differences and is therefore not suitable.