UGC NET Questions (Paper – 1)

Bloom’s framework distinguishes cognitive, affective and psychomotor domains. Demonstrating a titration requires precise hand movements, coordination and control of apparatus, so the behaviour belongs mainly to the psychomotor domain.

Option A:
Option A, the cognitive domain, concerns knowledge and mental skills like remembering, understanding and problem solving. Conceptual knowledge of titration is cognitive, but the act of performing it is motor-skill based.

Option B:
Option B correctly identifies the psychomotor domain, which includes manual and physical skills. Accurate titration demands fine motor control and coordinated actions, matching this domain.

Option C:
Option C, the affective domain, deals with attitudes, values and feelings. Liking laboratory work is affective, but actually doing titration is primarily psychomotor.

Option D:
Option D refers to a social domain, which is not one of the original three domains in the classic taxonomy. Titration can be performed individually without social interaction.

Remedial teaching focuses on helping learners who have not achieved expected levels of performance due to specific gaps or misconceptions. It is based on prior diagnosis of their difficulties through tests or observation. The aim is to provide targeted instruction and practice to overcome these problems. Therefore, the specialised teaching described in the stem is correctly termed remedial teaching.

Option A:
Remedial teaching involves adapting content, method and pace to suit learners who need extra help. It often includes re-teaching, additional examples and close monitoring. Since the stem emphasises instruction after identifying difficulties, remedial is the precise label that fits.

Option B:
Formal teaching refers broadly to structured education within an institution and does not specifically denote corrective instruction after diagnosis. It includes both regular and remedial work.

Option C:
Incidental teaching happens informally as opportunities arise, without planned correction of diagnosed problems, so it does not capture the targeted nature of remediation.

Option D:
Mass teaching suggests instruction delivered to large groups without individualisation, which is the opposite of the focused, corrective approach used in remedial programmes.

Memory level teaching emphasises rote learning and verbatim recall of information. Students are expected to reproduce definitions,facts and formulae exactly as given. There is little requirement for interpretation or application. The stem describes this type of learning situation precisely,so the appropriate level is memory.

Option A:
Memory level is considered the lowest level in this framework because it does not significantly develop reasoning or problem-solving. However,it can provide a foundation of basic information. Since the question emphasises repetition without understanding,this option is correct.

Option B:
Reflective level teaching requires learners to analyse,evaluate and make independent judgements,which goes far beyond simple repetition. Therefore,it does not match the situation in the stem.

Option C:
Understanding level teaching involves grasping meanings and relationships,so students can explain concepts in their own words; that is clearly not what is happening when only definitions are repeated.

Option D:
Creative is not a standard level in this tri-level model and in any case would involve original production,which is absent from the description of rote recall.

The pattern can be described by aₙ = 2n! + n² with n starting from 1. For n = 1, 2, 3, 4 and 5, this yields 2·1! + 1² = 3, 2·2! + 2² = 8, 2·3! + 3² = 21, 2·4! + 4² = 64 and 2·5! + 5² = 265, matching the given terms. For n = 6, we obtain a₆ = 2·6! + 6² = 2·720 + 36 = 1476. Thus 1476 is the only value that fits this factorial-based rule and continues the series.

Option A:
Option A, 1452, is 24 less than the correct value given by 2n! + n² at n = 6. To pick 1452 we would need to subtract 24 from the computed result only at this position, which would disrupt the pattern of combining factorial and square terms. Therefore option A is incorrect.

Option B:
Option B, 1476, exactly matches the number produced by 2·6! + 6². It preserves the factorial component and the quadratic addition in the same way as for earlier values of n. Because it extends the rule without any modification, this option correctly continues the series.

Option C:
Option C, 1464, is 12 smaller than the correct value and cannot be expressed as 2·720 + 36. It is only an approximate candidate and does not reflect the precise functional relationship. As such, option C is not a valid next term.

Option D:
Option D, 1488, is 12 greater than the required value and again fails to satisfy the formula at n = 6. Choosing 1488 would overstate the term in comparison to what the rule dictates, breaking the pattern. Hence option D is not acceptable.

This sequence is defined by a₁ = 3 and aₙ₊₁ = 4aₙ + n² + 1 for n ≥ 1. Applying the rule yields a₂ = 4·3 + 1² + 1 = 14, a₃ = 4·14 + 2² + 1 = 61, a₄ = 4·61 + 3² + 1 = 254 and a₅ = 4·254 + 4² + 1 = 1033, matching the given terms. For n = 5 the next term is a₆ = 4·1033 + 5² + 1 = 4158. Therefore 4158 is the unique number that continues the same recurrence correctly.

Option A:
Option A, 4126, is 32 less than the recurrence output for n = 5. To obtain 4126 we would need to subtract 32 from the formula result at the last step, which is not consistent with the earlier pattern. Hence this option does not follow the rule and is incorrect.

Option B:
Option B, 4142, is closer but still 16 less than the correct value 4158. It cannot be expressed as 4a₅ + 5² + 1 and would imply undercounting the contribution of the square term. As the recurrence is satisfied exactly before, option B cannot be the correct continuation.

Option C:
Option C, 4148, is slightly below the required value and also fails to satisfy the recurrence exactly. Selecting 4148 would again require modifying the output of the rule only at this step. Such a change destroys the strict structure of the sequence, so this option is not valid.

Option D:
Option D, 4158, equals exactly the result produced by aₙ₊₁ = 4aₙ + n² + 1 when n = 5. It maintains the process of quadrupling the previous term and adding a quadratic plus constant correction. Because this description explains each transition and leads naturally to 4158, option D is correct.

NEP 2020 states that the middle stage introduces more abstract concepts and formal subjects like science, mathematics, arts and humanities. However, pedagogy remains experiential and inquiry-based, with projects and group work. This stage prepares students for deeper secondary-level learning.

Option A:
Memorisation alone is rejected as insufficient and outdated.

Option B:
This option correctly blends subject specialisation with continued emphasis on activity-based, critical learning.

Option C:
Removing science and mathematics is completely contrary to the aims of the policy.

Option D:
Board exams occur later; middle stage should not be exam-centric.

Statements A, B and D accurately describe case study research as an in-depth exploration of a bounded system using multiple data sources to develop a rich contextual understanding. Case studies often focus on detailed narratives and interpretations rather than large-scale numerical data. Statement C is false because case studies are frequently qualitative, and E is false because insights from single or multiple cases can inform and refine theory, even if generalisation is limited.

Option A:
Option A includes only A and B and omits D, which recognises that case studies are valued for their context-specific depth of understanding. Without D, the distinctive contribution of case study research to rich description and interpretation is underplayed.

Option B:
Option B is correct because it combines the three true statements about what case studies are, how they are conducted and what kind of understanding they yield. It correctly excludes C and E, which misrepresent their quantitative nature and theoretical contribution.

Option C:
Option C lists B and D but leaves out A, so it does not specify that the focus is on a bounded system such as a particular person or institution. This definitional element is important, and its absence makes the combination incomplete.

Option D:
Option D includes E, the claim that case studies can never inform theory, which contradicts many examples where case-based insights have shaped theoretical ideas. Therefore, this option mixes a false statement with true ones and cannot be accepted.

If A alone finishes the work in 10 days, A’s one-day work is 1/10 of the job. If B alone finishes in 15 days, B’s one-day work is 1/15. The ratio of work done by A to work done by B in one day is (1/10):(1/15) = 15:10, which simplifies to 3:2. Thus, the required ratio is 3:2.

Option A:
Option A, 2:3, reverses the correct comparison and implies B does more work per day than A, suggesting B is faster. This contradicts the completion times, because A finishes in fewer days than B and must therefore have the higher daily rate.

Option B:
Option B, 4:3, does not match the exact fraction (1/10)/(1/15) = 15/10 = 3/2. While 4:3 is close numerically to 3:2, the calculation from the given times unambiguously leads to 3:2, not 4:3. Hence 4:3 is incorrect.

Option C:
Option C is correct because it faithfully reflects the inverse relationship between time and rate for a fixed amount of work. Shorter time (10 days) corresponds to a larger rate, and the ratio of these rates simplifies precisely to 3:2.

Option D:
Option D, 5:3, exaggerates the difference between the two rates beyond what is implied by 10 and 15 days. Using 5:3 would not produce the correct individual times if we converted back from the rate ratio, so it cannot be accepted.

Statements B, C and D are correct because they show how environmental management and rural development are linked. Watershed projects support conservation and productivity, agroforestry offers multiple benefits while protecting resources and ignoring sustainability can degrade land and water in the long run. Statement A is incorrect as watershed programmes are not confined to infrastructure building but emphasise conservation and resource management. Hence, the combination containing B, C and D only is the correct answer.

Option A:
Option A is incorrect because it includes only B and C and omits D, even though D is a true statement about the risks of environmentally insensitive rural development strategies. Leaving out a correct statement results in an incomplete representation of the topic.

Option B:
Option B is correct because it captures all the true statements—B, C and D—and excludes the false claim in A. It acknowledges conservation benefits, agroforestry’s role and the need for sustainability in rural development planning, which together reflect the integrated approach promoted in the syllabus.

Option C:
Option C is incorrect because it includes statement A, which mischaracterises the objectives of watershed development. While B and C are correct, adding A means the option no longer represents only correct statements.

Option D:
Option D is incorrect since it asserts that all four statements are correct. Accepting A as correct would imply that watershed development is restricted to roads and markets, which contradicts its actual conservation focus. Therefore, the entire combination cannot be chosen.

This series alternates between adding 5 and multiplying by 2. Starting from 4 we have 4 + 5 = 9, 9 × 2 = 18, 18 + 5 = 23, 23 × 2 = 46 and 46 + 5 = 51. The next step should therefore apply the multiplication operation. Hence, the next term is 51 × 2 = 102, which follows the established alternation.

Option A:
Option A gives 100, which does not result from either adding 5 or multiplying by 2 to 51. It introduces a new and unsupported operation into the sequence. Therefore, 100 is not compatible with the observed pattern.

Option B:
Option B yields 102, exactly equal to 51 × 2 and in perfect agreement with the alternating "+5, then ×2" rule. The series 4, 9, 18, 23, 46, 51, 102 remains structured and predictable under this rule. Hence, 102 is the correct next term.

Option C:
Option C suggests 104, which cannot be derived from either +5 or ×2 applied to 51. It would force an arbitrary adjustment not present in any earlier step. Thus, 104 is not the correct continuation.

Option D:
Option D presents 106, which is even further from the expected result of 51 × 2. This value does not fit the consistent alternating operations used to build the series. Therefore, 106 must be rejected.