UGC NET Questions (Paper – 1)

AIQ, BJR, CKS and DLT each consist of three letters that are widely separated by the same fixed distance in the alphabet. At the same time, the first letters move A, B, C, D, the second letters I, J, K, L and the third letters Q, R, S, T, all in simple one step sequences. Extending these sequences gives E as the next first letter, M as the next second letter and U as the next third letter. Together they form EMU, which preserves both the wide equal spacing inside the group and the column wise progression, so EMU is the correct continuation.

Option A:
Option A, EMT, uses E and M correctly but leaves the last letter at T, failing to move the third column forward by one. This breaks the clear sequence Q, R, S, T, U in the last position. Because it does not update every column consistently, EMT cannot be the right answer.

Option B:
Option B is correct because EMU keeps the same distance between its letters as the earlier groups and advances each column exactly one step. The triple A→B→C→D→E, I→J→K→L→M and Q→R→S→T→U continues without interruption. This perfect alignment with the observed pattern makes EMU the only valid next term.

Option C:
Option C, FNV, moves the starting letter two positions ahead of D instead of one and also shifts the others in a way that does not maintain the fixed internal gap. The vertical sequences would be broken in every column. Therefore FNV does not fit the series.

Option D:
Option D, ENU, begins with E but skips one step in the second column by jumping from L to N. This distorts the regular one step middle column progression. As it fails to keep the sequences intact, ENU is not an acceptable continuation.