Each group uses a constant +6 jump: (1,7,13,19), (2,8,14,20), (3,9,15,21), (4,10,16,22). Next is (5,11,17,23) = EKQW.
Option A:
Option A starts at F and does not match the required positional set.
Option B:
Option B is correct because it continues both the +1 shift in the first letter and the +6 internal spacing.
Option C:
Option C breaks the fixed +6 spacing.
Option D:
Option D breaks the fixed +6 spacing (E to J is +5, not +6).
Comment Your Answer
Please login to comment your answer.
Sign In
Sign Up
Answers commented by others
No answers commented yet. Be the first to comment!