UGC NET Questions (Paper – 1)

Each term shifts every letter by +2: ACEG→CEGI→EGIK→GIKM. Next is GIKM shifted by +2 to IKMO.

Option A:
Option A is correct because it applies the same +2 shift to each letter and keeps the +2 internal spacing.

Option B:
Option B does not come from adding +2 to each letter of GIKM.

Option C:
Option C breaks the internal spacing because M→N is +1.

Option D:
Option D starts with J instead of I, so it is not the +2 shift continuation.

Each group has the first three letters in strict consecutive order and the fourth letter repeats the first one. The sequences KLMK, LMNL, MNOM and NOPN show starting letters K, L, M and N moving one step forward each time. The next starting letter should therefore be O, and the first three letters become O, P and Q, with the fourth letter repeating O, giving OPQO.

Option A:
Option A, OPQP, begins with the correct three consecutive letters but ends with P, which repeats the second letter instead of the first. This violates the clear pattern that the final position mirrors the first letter. As a result, OPQP does not fit the established structure.

Option B:
Option B, PQOP, rearranges the letters so that the first three are no longer consecutive and the last letter is not a repetition of the first. It breaks both the ordering and the mirror condition of the groups. Therefore PQOP cannot be the correct continuation.

Option C:
Option C is correct because it keeps O, P and Q in consecutive order and then places O again in the fourth position. This continues the sequence of starting letters and respects the rule that the last letter must match the first. For these reasons, OPQO is the logical next term.

Option D:
Option D, NQPN, uses letters that do not form a simple consecutive run at the beginning and also fails to repeat the first letter at the end. The pattern of both order and repetition is lost, so NQPN does not align with the series.

Observing BEHK, EHKN, HKNQ and KNQT shows that each new group is obtained by adding the same number of positions to every letter of the previous group. BEHK shifts to EHKN, then to HKNQ and then to KNQT through a fixed forward movement in all four positions. Applying the same transformation to KNQT moves K, N, Q and T each ahead by the same amount, giving NQTW. Since NQTW alone is produced by this uniform large shift, it is the correct next term.

Option A:
Option A is correct because NQTW continues the chain of starting letters B, E, H, K to N and does the same for the other three columns. The internal relations among the letters remain unchanged as each one advances together. This preserves the defining property of the series and makes NQTW the logical continuation.

Option B:
Option B, NQUW, alters the third letter differently from the way earlier groups were transformed and does not reflect the same equal shift in every position. Its letters no longer align cleanly with the vertical sequences. Because it breaks the common movement, NQUW is not valid.

Option C:
Option C, OQTW, starts with O instead of N, pushing the first letter too far ahead and changing the step size. The rest of the letters also do not follow the precise transformation seen in the series. Therefore OQTW does not satisfy the pattern.

Option D:
Option D, MPSV, changes several letters in a way that cannot be explained by a single consistent shift applied to KNQT. It invents a different structure rather than extending the existing one. As a result, MPSV cannot be accepted as the next term.