UGC NET Questions (Paper – 1)

A number divisible by 4 must be divisible by 2, so it is even; no number that is a multiple of 4 can be odd. Likewise, any number divisible by 6 must also be divisible by 2, because 6 = 2 × 3, so divisibility by 6 implies divisibility by 2. Therefore, either statement by itself guarantees that x is even. Since each statement is independently enough to answer the question, each alone is sufficient.

Option A:
Option A underestimates statement (2), but divisibility by 6 already includes divisibility by 2, so statement (2) is also sufficient.

Option B:
Option B reverses the mistake by underestimating statement (1), though any multiple of 4 is clearly even.

Option C:
Option C claims that only the combination of statements can decide parity, which is wrong because each provides its own independent guarantee of evenness.

Option D:
Option D correctly recognises that both conditions individually ensure x is even, making each statement sufficient on its own.