UGC NET Questions (Paper – 1)

Statements A, B, C and E are all correct: they define the arithmetic mean, describe how adding a constant shifts the mean, explain that the updated mean lies between the old mean and the new value, and note that weighted averages incorporate differing importance through weights. Statement D is false because the average need not coincide with any actual data point; for example, the mean of 2 and 4 is 3, which is not in the list. Therefore, the combination that includes A, B, C and E and excludes D is correct.

Option A:
Option A is incomplete since it does not mention E and therefore overlooks the important idea that some aptitude problems require weighted averages rather than simple means. Without E, the concept coverage is narrower than intended.

Option B:
Option B is also incomplete: although B, C and E are true, the omission of A means the basic definition of arithmetic mean is missing. A must be included to fully represent how averages are computed.

Option C:
Option C is correct as it brings together all the true statements about how means behave and how weighted averages work, while rejecting D, which mistakenly claims that the mean must be an actual data value. It provides a complete conceptual picture for NET-level questions.

Option D:
Option D is wrong because it includes D, the false statement about averages always equalling a data point, and omits B, which correctly summarises the effect of adding a constant. This mixture makes the option logically inconsistent.