UGC NET Questions (Paper – 1)

To convert binary to octal, we group the bits in triples from the right. The number 111011110 becomes 111 011 110. Each group is then converted: 111₂ = 7₈, 011₂ = 3₈, and 110₂ = 6₈. Combining these octal digits gives 736₈ as the equivalent of 111011110₂.

Option A:
Option A, 756, would correspond to binary groups 111 101 110, which is different from the original 111 011 110.

Option B:
Option B, 7360, implies an extra 3-bit group (or trailing zeros) that are not present in the given binary numeral.

Option C:
Option C, 734, would correspond to 111 011 100; the last group does not match 110.

Option D:
Option D, 736, comes directly from converting 111, 011, and 110 into 7, 3, and 6.