UGC NET Questions (Paper – 1)

To convert binary to octal, we group bits in sets of three from right to left. For 111100101₂, we group as 111 100 101. These triplets correspond to 7, 4, and 5 in octal respectively. Placing these digits together, we obtain 745₈ as the octal representation.

Option A:
Option A accurately reads each 3-bit group: 111₂→7, 100₂→4, and 101₂→5. This direct mapping is standard for binary–octal conversion and yields 745₈ from the given binary sequence.

Option B:
Option B, 753₈, implies the middle group is 101₂ instead of 100₂, altering the middle digit from 4 to 5. This does not match the actual bits in the binary number, so it is incorrect.

Option C:
Option C, 765₈, changes both the middle and last triplets, implying 110₂ and 101₂ or other combinations, which are inconsistent with the original 111100101₂. Thus, it does not correspond to the given pattern.

Option D:
Option D, 755₈, also modifies the binary grouping, suggesting different 3-bit values than actually present. Since each octal digit must match a specific 3-bit group, this representation is invalid for the given binary number.