UGC NET Questions (Paper – 1)

In this series, the first letters move forward in the alphabet (A, B, C, D, …) while the second letters move backward from the end (Z, Y, X, W, …). The next first letter after D is E and the next second letter before W is V. Combining these gives the pair EV as the unique continuation that preserves both movements simultaneously. Therefore EV correctly continues the established pattern of opposite-direction shifts in the two positions.

Option A:
Option A is correct because its first letter E follows D and its second letter V precedes W, fitting the consistent forward–backward pattern. It respects the equal step size of one position for both directions of movement. No other option maintains this exact mirror-type structure on both letters at the same time. Thus EV is the only pair that logically continues the series.

Option B:
Option B, EU, keeps the first letter E correct but changes the second letter to U, which skips one extra position from W. This breaks the consistent one-step backward movement in the second letter (Z, Y, X, W, V). Because of this extra jump, EU does not fit the precise mirror pattern. Hence, it cannot be the correct continuation.

Option C:
Option C, FW, advances the first letter too far to F and freezes the second letter at W. The first letter should only move from D to E, not to F, and the second letter should continue decreasing instead of remaining the same. This double violation means FW fails to respect both directional rules of the series.

Option D:
Option D, GV, moves the first letter forward by three positions from D to G instead of by a single step. While the second letter V is what we expect, the incorrect jump in the first letter destroys the symmetry of the pattern. Because series questions require strict consistency, GV cannot be accepted as the next term.

Let the two numbers be 5x and 7x. Increasing the first by 20% gives 5x × 1.2 = 6x. Decreasing the second by 20% gives 7x × 0.8 = 5.6x, which is 28x/5. The new ratio is 6x : (28x/5) = (6 × 5)x : 28x = 30x : 28x = 15:14. Therefore, 15:14 is the required new ratio.

Option A:
Option A, 4:5, would correspond to a situation where the first number becomes relatively smaller than 5x and the second number remains close to 7x. This contradicts the specified percentage changes, where the first number actually grows and the second shrinks. So 4:5 cannot arise from the given operations.

Option B:
Option B, 6:5, incorrectly suggests that the new ratio reflects only the increased numerator without accounting for the reduction in the denominator. If we take 6:5, the implied percentage change for the second number does not line up with a 20% decrease from 7x. Thus, 6:5 is not consistent with the given data.

Option C:
Option C is correct because it incorporates both the 20% increase of the first number and the 20% decrease of the second number. The algebraic simplification of the resulting expressions leads cleanly to 15:14. This ratio reflects the combined effect of both changes accurately.

Option D:
Option D, 7:6, might be guessed from the original ratio 5:7 by swapping roles and adjusting slightly, but no such transformation is described in the question. When we compute the actual new values, they do not simplify to 7:6, so this option fails the mathematical check.

This series is described by the formula aₙ = 5n²+n−2 for n starting from 1. For n = 1, 2, 3, 4 and 5 we obtain 5·1²+1−2 = 4, 5·2²+2−2 = 20, 5·3²+3−2 = 46, 5·4²+4−2 = 82 and 5·5²+5−2 = 128. For n = 6 the same expression gives 5·6²+6−2 = 180+6−2 = 184. Therefore 184 is the correct next term under this quadratic rule.

Option A:
Option A, 174, is 10 less than the value predicted by 5n²+n−2 for n = 6. It does not fit the formula and would require arbitrarily lowering the computed term. Hence 174 is not consistent with the sequence’s structure.

Option B:
Option B, 184, exactly equals 5·6²+6−2 and so preserves the quadratic relationship between n and aₙ. It ensures that the same rule that explains all previous terms also generates the new one. For this reason, 184 is the correct continuation.

Option C:
Option C, 178, also deviates from the calculated value and does not arise from the given expression. It would amount to changing the pattern only at the last step, which is logically unsound. Thus 178 cannot be the right answer.

Option D:
Option D, 192, is larger than the formula’s result and again cannot be written as 5n²+n−2 for n = 6. Selecting 192 would break the precise connection between position and term, so it is not valid.

Each term is obtained by multiplying the previous term by 2: 5×2 = 10, 10×2 = 20 and 20×2 = 40. This defines a geometric progression with ratio 2. Applying the same rule gives 40×2 = 80. Thus, 80 is the correct next term that preserves the doubling pattern.

Option A:
Option A is 60, which would represent adding 20 to 40 rather than doubling. No earlier transition uses simple addition of a fixed number, so 60 does not fit the rule.

Option B:
Option B is 70, which involves adding 30 to 40 and lacks any basis in the preceding behaviour of the sequence. It fails to keep the constant ratio property. Hence, it is incorrect.

Option C:
Option C equals 80 and results directly from 40×2. The extended series 5, 10, 20, 40, 80 shows a clean geometric pattern. This makes 80 the unique choice that follows the same logic.

Option D:
Option D is 100, which would require a factor of 2.5 from 40. As the sequence has consistently used a ratio of 2, introducing 2.5 is unjustified. Therefore, this option is not valid.

Each term after the first is three times the previous term plus 1. We see 1×3+1 = 4, 4×3+1 = 13 and 13×3+1 = 40, and 40×3+1 = 121. Applying the same rule gives 121×3+1 = 363+1 = 364. Therefore, 364 is the correct next term.

Option A:
Option A preserves the recursive formula exactly, producing 364 from 121×3+1. The series 1, 4, 13, 40, 121, 364 remains internally consistent with a single clear rule. Hence, this option is correct.

Option B:
Option B is 360, which would require subtracting 3 after tripling, not adding 1. This contradicts the pattern seen in earlier steps. Therefore, 360 is not suitable.

Option C:
Option C is 400, which has no direct link with the 3×n+1 structure. It appears as a round number but does not arise from the required operation. Thus, 400 cannot be accepted.

Option D:
Option D is 500, an even larger value that also fails to result from 121×3+1. Choosing 500 would completely ignore the established multiplication-plus-one pattern. Therefore, this option is incorrect.

Statements A and B describe the core task and one possible sufficiency pattern, D highlights that sometimes both statements together are needed and E correctly notes that these questions focus on judging sufficiency rather than performing detailed computation. Statement C is false because in many data sufficiency items it is enough to determine that a unique answer can be found in principle, without actually computing it. Therefore, the combination A, B, D and E only is correct.

Option A:
Option A is incomplete because it omits E and so underplays the fact that data sufficiency emphasises reasoning about information rather than heavy calculation. Without E, the skill focus of these questions is not fully captured.

Option B:
Option B is also incomplete since it leaves out A, failing to mention explicitly that the central goal is to determine sufficiency of information, not to solve the problem numerically. This omission weakens the conceptual framing.

Option C:
Option C is wrong because it includes C, the mistaken requirement to always compute exact answers, and it also omits E, thereby misrepresenting the very philosophy of data sufficiency questions.

Option D:
Option D is correct because it contains all the true statements about how sufficiency is judged and how statements are used, while excluding C, which contradicts standard instructions for such items. It aligns with UGC NET-style data sufficiency patterns.

The given terms are squares of consecutive integers: 4² = 16, 5² = 25, 6² = 36 and 7² = 49. The next integer is 8, so the next term should be 8². Calculating 8² gives 64. Thus, 64 correctly continues the sequence.

Option A:
Option A matches the pattern because it is 8² and follows directly after 7². The extended list 16, 25, 36, 49, 64 represents squares of 4, 5, 6, 7 and 8. This makes the rule clear and consistent.

Option B:
Option B is 56, not a perfect square of any integer and lying between 7² and 8². It cannot be justified under the consecutive square rule. Hence, it is not correct.

Option C:
Option C is 60, which again is not a perfect square and has no natural connection to the sequence. Including it would break the neat square pattern. Therefore, 60 cannot be accepted.

Option D:
Option D is 72, which also is not a perfect square and sits above 8². This choice does not respect the structure based on exact squares. Thus, it is not appropriate.

Statement A describes how line graphs display data as connected points, often across time. Statement B is correct because line graphs are designed to show trends and changes over intervals clearly. Statement D is also true; in exams candidates often estimate values when scale markings are coarse. Statement C is false since multiple lines are precisely used to compare series, and E is false because years and months are very common on the horizontal axis for such graphs. Thus A, B and D only are correct, which matches option B.

Option A:
Option A is incomplete because it leaves out D, failing to mention the practical aspect of approximate reading from line graphs, which is typical in NET data interpretation.

Option B:
Option B is correct as it gathers the basic definition, the main use for detecting trends and the realistic need for approximation, while excluding C and E, which misrepresent the comparative and temporal use of line graphs.

Option C:
Option C is wrong because it includes E, which wrongly bans years or months on the axis, and it omits A, thereby combining an error with the omission of a central property.

Option D:
Option D is incorrect since it includes C, which claims that simultaneous comparison is impossible, when in fact it is one of the main reasons for drawing multi-line graphs.

According to the BODMAS rule, division and multiplication are performed before addition and subtraction and are evaluated from left to right. Starting with 18 ÷ 3, we get 6, then multiplying 6 × 2 gives 12. The expression now becomes 12 + 12 − 4. Next, we perform addition and subtraction from left to right: 12 + 12 = 24 and then 24 − 4 = 20. Thus, the value of the expression is 20.

Option A:
Option A, 16, might result from an incorrect grouping of operations, such as performing addition or subtraction too early, but it does not respect the proper order dictated by BODMAS.

Option B:
Option B, 18, could arise from partial simplification without completing all operations in the correct sequence, but it fails to match the fully evaluated expression.

Option C:
Option C consistently applies the order of operations, handling division and multiplication first, then addition and subtraction. This careful sequencing leads to the accurate result of 20.

Option D:
Option D, 22, again does not correspond to the correct application of BODMAS and suggests an arithmetic error in combining the intermediate results.

B is the definition of a GP (constant common ratio). C is true for positive terms when r > 1. D is true for positive terms when 0 < r < 1. A is false (that describes an AP), and E is false (a GP is not generally an AP). Therefore B, C and D only are correct. Option A: Option A is incomplete because it omits D, the key decreasing-case when 0 < r < 1. Option B: Option B is incorrect since it includes E, which falsely claims every GP is an AP. Option C: Option C is correct because it includes exactly the true statements (B, C, D) and excludes A and E. Option D: Option D is wrong because it includes A, which incorrectly describes a GP as having a fixed additive difference.

Statements A, B, C and D correctly describe the standard structure of a categorical syllogism: it has two premises and one conclusion, with the major term as predicate, the minor term as subject and the middle term linking the premises but not appearing in the conclusion. Statement E is false because a syllogism with two negative premises is invalid; such premises fail to provide a constructive linkage between terms. Thus the combination containing A, B, C and D and excluding E is the only fully correct option.

Option A:
Option A is correct since it includes all structural truths about categorical syllogisms while rejecting E, which misstates a condition for validity. It reflects rules that are often checked using Venn diagrams in NET questions.

Option B:
Option B is incomplete because although A, B and C are true, it omits D, so it does not explain the crucial role of the middle term in linking the premises without appearing in the conclusion. Without D, the structure is only partially described.

Option C:
Option C is incorrect because it includes E, the false claim that two negative premises yield validity, and excludes B, so it both admits an invalid rule and omits a correct one. This makes the combination logically unsound.

Option D:
Option D is wrong because it leaves out A and therefore fails to note that the standard syllogism has exactly two premises and one conclusion. While B, C and D are true, omitting A gives an incomplete account of the syllogistic form.

The sequence can be defined recursively by a₁ = 7 and aₙ₊₁ = 3aₙ + n² for n ≥ 1. Using this rule, a₂ = 3·7 + 1² = 22, a₃ = 3·22 + 2² = 70, a₄ = 3·70 + 3² = 219 and a₅ = 3·219 + 4² = 673, matching the given terms. For n = 5 the next term is a₆ = 3·673 + 5² = 2044. Thus 2044 is the only value that satisfies the same recurrence and correctly continues the series.

Option A:
Option A, 2044, is exactly the result produced by aₙ₊₁ = 3aₙ + n² when it is applied to a₅ with n = 5. It preserves the pattern of tripling the previous term and adding the square of the index. Because this rule explains each step of the sequence and yields 2044 next, this option is correct.

Option B:
Option B, 2032, is 12 less than the recurrence output for n = 5. To accept 2032 we would have to arbitrarily subtract 12 from the correctly computed value while keeping the rule unchanged before. Such a disturbance is not justified by the earlier progression, so option B is incorrect.

Option C:
Option C, 2056, is 12 more than the required value from the recurrence. Selecting 2056 would similarly require increasing the formula result only at this final step. That would break the precise relationship described by aₙ₊₁ = 3aₙ + n², making option C invalid.

Option D:
Option D, 2072, deviates even further from the recurrence value and cannot be written as 3·673 + 5². Using 2072 would disregard the established rule and destroy the exact fit observed in earlier terms. Therefore this option does not correctly continue the series.

Compound interest for 2 years at 10% per annum is computed using the amount formula A = P(1 + R/100) raised to the power of time. Here, A = 10,000 × (1 + 10/100)² = 10,000 × (1.1)². The value of (1.1)² is 1.21, so the amount becomes 10,000 × 1.21 = 12,100. The compound interest is the amount minus the principal, which is 12,100 − 10,000 = ₹2,100.

Option A:
Option A, ₹1,000, equals simple interest for one year at 10% but fails to account for the interest-on-interest effect in the second year. It underestimates the total interest earned over two years.

Option B:
Option B, ₹2,000, corresponds to simple interest over two years (10% each year on the principal only), but compound interest is slightly higher because the second year’s interest is also earned on the first year’s interest.

Option C:
Option C correctly derives the amount using the compound interest factor (1.1)² and subtracts the original principal. This procedure captures the compounding process and yields the slightly larger interest of ₹2,100.

Option D:
Option D, ₹2,200, overstates the effect of compounding and would require a higher effective rate or more time than actually given in the problem.

The rule states that each letter is replaced by the next letter in the alphabet. For the word NET, N is followed by O, E is followed by F and T is followed by U. Replacing each letter accordingly, N becomes O, E becomes F and T becomes U, giving the code OFU. This maintains the same pattern that was used to convert WORD into XPSE.

Option A:
Option A correctly shifts every letter of NET forward by one position, providing O from N, F from E and U from T. It applies the coding rule consistently to all positions and thus matches the example given.

Option B:
Option B, OEU, shifts only some letters correctly and uses E instead of F for the second position. This breaks the uniform next-letter rule for the middle letter.

Option C:
Option C, MFS, shifts N backwards to M instead of forwards and only partially follows the pattern. It does not consistently apply the specified direction of shift.

Option D:
Option D, NEU, keeps N unchanged, which contradicts the rule that each letter must be replaced by its immediate successor in the alphabet.

Inside each group, the distances from one letter to the next follow a repeating pattern of unequal steps. ACFH, BDGI, CEHJ and DFIK all show the same sequence of jumps between their letters. From term to term, every letter in a given position moves forward by one, creating four simple vertical sequences across the series. Shifting each letter in DFIK forward by one gives EGJL, which keeps the characteristic internal spacing and extends each of the column sequences, so it is the correct next term.

Option A:
Option A, EGIK, uses letters that look close to the right ones but breaks the established distances between the third and fourth letters. The internal pattern that links the positions is not preserved exactly. Because the spacing inside EGIK does not match that of the previous terms, it cannot be the continuation.

Option B:
Option B, EFJL, alters more than one column and does not arise from adding one to every letter of DFIK. Its letters do not line up properly with the existing vertical progressions. As a result, EFJL is inconsistent with the simple column wise rule that drives the series.

Option C:
Option C is correct because EGJL is obtained by applying the same transformation to DFIK that relates each pair of earlier neighbours. It respects the specific jumps inside each group and the one step advancement in every column. This complete agreement with both components of the pattern makes EGJL the only valid next term.

Option D:
Option D, FGJM, shifts the starting letter too far forward and changes the later letters in a way that no longer matches the earlier spacing pattern. The resulting group would break the smooth development of the series. Therefore FGJM is not a suitable continuation.