Three-letter groups step of three – UGC NET Question

The starting letters L, O, R and U are at positions 12, 15, 18 and 21 in the alphabet, increasing by 3 each time. Each group is made of three consecutive letters in forward order. Continuing the same pattern, the next starting position is 24, which corresponds to X, and the following letters are Y and Z, giving XYZ. Thus XYZ maintains both the constant plus three gap and the consecutive structure.

Option A:
Option A, WXY, starts at W, which is position 23 and only two steps ahead of U, so it does not satisfy the required three position jump. While WXY is a set of consecutive letters, it does not arise from the same arithmetic rule for starting letters. Therefore it cannot represent the logical continuation of the series.

Option B:
Option B, VWX, begins at V, which is position 22 and only one step beyond U. This reduces the gap rather than maintaining the plus three pattern. Since all previous transitions show a fixed increase of three, VWX is inconsistent with the established trend and thus incorrect.

Option C:
Option C is correct because X is exactly three positions after U and XYZ forms a clean block of three consecutive letters. It extends the same numerical pattern in the first letter and keeps the internal arrangement of letters unchanged. This dual consistency makes XYZ the only suitable next term.

Option D:
Option D, YZA, uses Y as the starting letter, which is four positions ahead of U, overshooting the required step. It also wraps into the next cycle of the alphabet before the pattern naturally demands it. For these reasons, YZA does not accurately continue the given series.