Letter series Z W T Q N – UGC NET Question

The positions of these letters are Z(26), W(23), T(20), Q(17) and N(14). The difference between consecutive terms is −3 each time (26→23, 23→20, 20→17, 17→14). Continuing the same rule, the next position is 14 − 3 = 11, which is the letter K. Therefore K is the unique letter that preserves the constant backward step of 3.

Option A:
Option A, L, is at position 12, which is only 2 steps behind N at 14. This contradicts the strict pattern of subtracting 3 from the position each time. Because L does not maintain the consistent decrement, it cannot be part of the series.

Option B:
Option B, M, corresponds to position 13, giving a difference of 1 from N. There is no indication that the size of the backward step is reducing as the series progresses. Since the pattern clearly shows a constant −3, M fails to fit the rule.

Option C:
Option C, J, is at position 10, which is 4 positions behind N. This would increase the backward jump to −4, altering the original rule of the sequence. As there is no evidence of changing step sizes, J does not correctly continue the series.

Option D:
Option D is correct because K is at position 11, exactly 3 positions before N. This maintains the uniform backward movement that characterises the sequence. Keeping the decrement constant is essential for logical consistency, so K is the only valid next term.