Four-letter groups even step start – UGC NET Question

The groups are four letter consecutive blocks where the starting letters J, L, N and P occupy positions 10, 12, 14 and 16, increasing by 2 each time. Each block then takes the next three letters in order. Continuing this rule, the next starting letter is position 18, which is R, and the block from R is RSTU. Thus RSTU uniquely keeps both the plus two starting step and the four letter structure.

Option A:
Option A, STUV, is a valid four letter block but begins at S, which is three steps after P instead of two. This changes the size of the jump in the starting letter, contradicting the constant increment of two. Therefore STUV does not align with the governing rule of the series.

Option B:
Option B, QRST, starts at Q, which is only one position after P. That reduces the step from two to one and breaks the arithmetic progression of starting positions. Because the pattern clearly shows a consistent plus two movement, QRST cannot be considered correct.

Option C:
Option C is correct because R is exactly two positions ahead of P and RSTU forms a proper four letter consecutive group. It extends the same even step difference in the starting letter and preserves the internal consecutiveness. This match with both structural aspects of the series makes RSTU the right answer.

Option D:
Option D, NOPQ, repeats an earlier block instead of moving forward. The series never reuses a previous group, and each term has a strictly increasing starting letter. As a result, NOPQ cannot be the next term.