Four-letter even-position progression – UGC NET Question

Each group consists of letters that are two positions apart inside the alphabet. Comparing successive groups shows that each letter in the group shifts forward by one position at every step. BDFH moves to CEGI, which moves to DFHJ, then to EGIK. Shifting E, G, I and K one position forward gives F, H, J and L, forming FHJL.

Option A:
Option A, FGIK, changes some letters but does not represent the result of adding one to each letter of EGIK. In particular, G should become H and I should become J, which FGIK does not implement. Because it fails to apply a uniform one step shift to all four letters, FGIK does not follow the pattern.

Option B:
Option B, FGIJ, keeps the first two letters plausible but breaks the regular spacing between the letters and the consistent one position shift from EGIK. The transformations from G to G and from K to J are not aligned with the plus one rule. Therefore FGIJ is not a logical continuation.

Option C:
Option C is correct because F, H, J and L are obtained by adding one to E, G, I and K respectively. It maintains both the two position spacing within each group and the equal shift of one between successive groups. This perfect parallel movement in all positions makes FHJL the only term that fits the series.

Option D:
Option D, GHJM, alters the spacing and does not arise from applying the same transformation to each letter of EGIK. Some letters move more than one step while others move inconsistently. As a result, GHJM fails to capture the structure of the pattern.