Even number divisibility by two – UGC NET Question

This option is correct because an even number is defined as any integer that can be written as 2k for some integer k. Being a multiple of 2 means the number fits this form. Therefore, any multiple of 2 is an even number.

Option A:
Even numbers have 2 as a factor and are exactly divisible by 2. Writing the number as 2k shows it is a multiple of 2, which matches the condition in the question. Thus, this option is correct.

Option B:
Odd numbers are not multiples of 2 and leave a remainder of 1 when divided by 2. Since the question specifies multiples of 2, odd numbers cannot be the correct classification.

Option C:
Prime numbers are defined by having exactly two distinct positive divisors. Some primes like 2 are even, but not all multiples of 2 are prime. Many even numbers have more than two divisors, so prime is not the right general term here.

Option D:
Composite numbers have more than two positive divisors and can be even or odd. The phrase "multiple of 2" points specifically to evenness, not to the broader idea of compositeness. Hence, this option is not precise enough.