Binary of octal 73 – UGC NET Question

Each octal digit converts to a 3-bit binary pattern. For 73₈, the digit 7 maps to 111₂ and the digit 3 maps to 011₂. Combining these gives 111011₂. This pattern is the binary equivalent of the octal number 73.

Option A:
Option A is correct because 7→111₂ and 3→011₂, so 73₈ becomes 111011₂. This maintains the positional values exactly across bases.

Option B:
Option B, 111101₂, would represent octal 75₈, since 101₂ corresponds to 5. It therefore does not match the given octal number.

Option C:
Option C, 110111₂, maps back to octal 67₈, with groups 110₂ and 111₂ representing 6 and 7. This differs from 73₈.

Option D:
Option D, 101111₂, would correspond to octal 57₈. The grouping of bits does not align with 73₈.