UGC NET Questions (Paper – 1)

The series consists of overlapping three letter blocks in forward order, while the starting letter moves backward by one each time. Starting letters S, R, Q and P occupy positions 19, 18, 17 and 16, decreasing by 1. The next starting letter must therefore be O at position 15, leading to the block OPQ. This group keeps the internal order and the backward movement of the starting position.

Option A:
Option A, ONP, uses the correct starting letter O but arranges the remaining letters out of consecutive order. The letters N and P do not appear in correct sequence following O. Because each group in the series is strictly built from consecutive letters in increasing order, ONP is not acceptable.

Option B:
Option B, PQR, repeats the last given group instead of moving to the next starting letter. The pattern does not involve repetition; it consistently shifts the starting point backward along the alphabet. For that reason, PQR cannot be the next term.

Option C:
Option C, NOP, starts at N, which is two positions before P rather than one. Although NOP is a consecutive block, it does not correctly mirror the one step backward movement seen in the starting letters. Therefore NOP breaks the established positional rule.

Option D:
Option D is correct because OPQ begins with O, exactly one step before P, and continues with P and Q in order. It maintains the overlapping structure and the uniform backward shift of the starting letter. This agreement with both the structure and movement of the series makes OPQ the logical continuation.

Each new group is formed by adding +1 to every letter: CAM→DBN→ECO→FDP. Next is FDP shifted to GEQ.

Option A:
Option A changes the second letter incorrectly and does not apply +1 uniformly.

Option B:
Option B uses D as the middle letter, which is not +1 from D in FDP (it should become E).

Option C:
Option C ends with R, which is +2 from P, not +1.

Option D:
Option D is correct because F→G, D→E, P→Q.

The groups are three consecutive letters and each new group starts two letters after the start of the previous one. The starting letters A, C, E and G correspond to positions 1, 3, 5 and 7, all increasing by 2. The next starting letter must therefore be position 9, which is I, and the group formed is IJK. This satisfies both the skip of one letter between starting positions and the three letter consecutive structure.

Option A:
Option A, HIJ, begins at H, which is position 8 and only one step after G. This ignores the observed pattern of moving the starting position by two positions. Although HIJ is a valid consecutive block, it does not respect the skip rule that defines the series.

Option B:
Option B, JKL, starts at J, which is position 10 and three positions after G. This overshoots the required increment and creates a larger gap than any previous step. Because the series maintains a consistent plus two movement, JKL cannot be correct.

Option C:
Option C, KLM, is even further ahead and increases the offset between starting letters even more. It would represent a later term in a continuation, not the immediate next group. As there is no jump of four positions in the given pattern, KLM does not fit the series.

Option D:
Option D is correct because I is exactly two positions after G, and IJK is a three letter consecutive group. It preserves the pattern of skipping one letter between the starting points and keeps the internal order unchanged. For these reasons, IJK is the logical continuation of the letter group series.

Starting letters W(23), T(20), Q(17), N(14) decrease by −3 each time. Next start is K(11), giving KLM.

Option A:
Option A starts at J(10), which is −4 from N, not −3.

Option B:
Option B is correct because K is −3 from N and L,M follow consecutively.

Option C:
Option C starts at L(12), which is −2 from N, not −3.

Option D:
Option D moves forward from N (breaks the backward pattern).

The starting letters M, P, S and V occupy positions 13, 16, 19 and 22, increasing by 3 each time. Each group is formed by three consecutive letters in forward order. Adding 3 to 22 gives 25, which is Y, and the next two letters after Y are Z and A, giving YZA with cyclic wrap around. Thus YZA is the unique group that continues the plus three pattern while respecting the cyclic nature of the alphabet.

Option A:
Option A, XYZ, starts at X, position 24, which is only 2 positions after V instead of 3. It therefore does not follow the consistent step of three seen in the starting letters. Even though XYZ is a consecutive group, it does not arise from the same generating rule.

Option B:
Option B, WXY, begins at W, position 23, just one step after V. This shrinks the required step and contradicts the established difference of three positions between starting letters. For this reason, WXY cannot be the correct continuation.

Option C:
Option C is correct because Y is position 25, exactly three positions beyond V, and YZA forms a three letter block progressing alphabetically with wrap around to A. It respects both the distance between starting letters and the internal consecutive pattern. This makes YZA the logical next term in the series.

Option D:
Option D, ZAB, starts at Z, which is four positions ahead of V when counting cyclically, not three. That would increase the gap and break the regularity of the step size. As the pattern does not show any such change, ZAB cannot be accepted.

Each group is a block of three consecutive letters, and each new group starts one letter later than the previous one: ABC (1–3), BCD (2–4), CDE (3–5) and DEF (4–6). Following this sliding pattern, the next block should be 5–7, which is EFG. Thus EFG is the only group that continues the shifting window of three letters.

Option A:
Option A is correct because it begins at E, the letter after D, and includes the next two letters F and G. This matches the structure of overlapping three-letter blocks. EFG therefore maintains both the length and the shifting start of the groups.

Option B:
Option B, FGH, starts at F instead of E, pushing the window too far forward. This would skip the block starting with E that the pattern demands. As a result, FGH does not fit the immediate continuation of the series.

Option C:
Option C, GHI, moves even further ahead, starting at G. It ignores the systematic one-letter shift in the starting position. Because the series does not skip starting letters, GHI cannot be the next term.

Option D:
Option D, BCD, repeats an earlier block rather than providing a new one. The pattern clearly produces new overlapping groups, not repetitions. Hence BCD is not a valid continuation.

Starting letters C(3), G(7), K(11), O(15) increase by +4. Next start is S(19), so the block is STU.

Option A:
Option A is correct because S is +4 from O and T,U follow consecutively.

Option B:
Option B starts at R(18), which is +3 from O, not +4.

Option C:
Option C starts at V(22), which is +7 from O, not +4.

Option D:
Option D starts at N(14), which goes backward and breaks the progression.

The starting letters L, O, R and U are at positions 12, 15, 18 and 21 in the alphabet, increasing by 3 each time. Each group is made of three consecutive letters in forward order. Continuing the same pattern, the next starting position is 24, which corresponds to X, and the following letters are Y and Z, giving XYZ. Thus XYZ maintains both the constant plus three gap and the consecutive structure.

Option A:
Option A, WXY, starts at W, which is position 23 and only two steps ahead of U, so it does not satisfy the required three position jump. While WXY is a set of consecutive letters, it does not arise from the same arithmetic rule for starting letters. Therefore it cannot represent the logical continuation of the series.

Option B:
Option B, VWX, begins at V, which is position 22 and only one step beyond U. This reduces the gap rather than maintaining the plus three pattern. Since all previous transitions show a fixed increase of three, VWX is inconsistent with the established trend and thus incorrect.

Option C:
Option C is correct because X is exactly three positions after U and XYZ forms a clean block of three consecutive letters. It extends the same numerical pattern in the first letter and keeps the internal arrangement of letters unchanged. This dual consistency makes XYZ the only suitable next term.

Option D:
Option D, YZA, uses Y as the starting letter, which is four positions ahead of U, overshooting the required step. It also wraps into the next cycle of the alphabet before the pattern naturally demands it. For these reasons, YZA does not accurately continue the given series.

Starting letters Z(26), V(22), R(18), N(14) decrease by −4. Next start is J(10), giving JKL.

Option A:
Option A starts at K (11), which is −3 from N, not −4.

Option B:
Option B is correct because J is −4 from N and K,L follow consecutively.

Option C:
Option C starts at H (8), which is −6 from N, not −4.

Option D:
Option D starts at G (7), which is −7 from N, not −4.

Every term is a block of three consecutive letters, and the starting letter moves backward by one each time: K, J, I, H → G. Hence GHI.

Option A:
Option A is correct because it continues the −1 slide to G and keeps the 3-letter consecutive block.

Option B:
Option B repeats a previous middle term (breaks the slide).

Option C:
Option C moves forward and breaks the backward slide.

Option D:
Option D jumps the starting letter too far back (−3), not −1.

Each group is made of three consecutive letters, but the starting letters do not progress uniformly. They move from A to C (+2), from C to F (+3) and from F to J (+4), so the gaps themselves increase by one each time. Following this rule, the next starting letter should be J + 5 = O, and the three consecutive letters from O are O, P and Q. Therefore OPQ is the correct continuation.

Option A:
Option A, MNO, begins at M, which would correspond to a gap of only +3 from J and ignores the observed +5 requirement. It would make the sequence of gaps 2, 3, 4, 3 instead of 2, 3, 4, 5. Since the pattern clearly shows increasing differences, MNO does not fit.

Option B:
Option B, NOP, starts at N, representing a gap of +4 from J and essentially repeats the previous increase. This would produce a flat sequence of gaps at the end instead of a steadily growing one. Because the rule is that each new gap increases by one, NOP cannot be the next term.

Option C:
Option C is correct because the starting letter O is exactly five positions after J, which extends the gap sequence 2, 3, 4 to 5. The letters P and Q follow in order, preserving the internal structure of each group as three consecutive letters. Hence OPQ is the only option that satisfies both the gap rule and the block structure.

Option D:
Option D, PQR, begins even further ahead at P, yielding a gap of +6 from J. This overshoots the expected step and makes the sequence of gaps jump from 4 to 6. As there is no evidence of such a sudden larger jump, PQR is not a valid continuation of the pattern.

The groups are consecutive three-letter blocks taken in order around the alphabet: PQR (16–18), STU (19–21), VWX (22–24) and YZA (25, 26, 1). After YZA, the next three consecutive letters are B, C and D, starting from the letter after A. Therefore BCD is the immediate next block, and the series continues cyclically.

Option A:
Option A, ABC, restarts at A but overlaps with the last letter of YZA and does not begin with the next letter after A. The pattern continues forward from A to B, not back to A again. Because ABC does not follow the “next-after-A” continuation, it is not consistent with the series.

Option B:
Option B, BCD, is correct because it starts from B, the next letter after A, and forms a three-letter consecutive block. This preserves both the block length and the cyclic progression across the alphabet. The group BCD therefore fits perfectly into the established rotation.

Option C:
Option C, CDE, skips directly to C as the starting letter, ignoring B, which should come immediately after A in the cycle. This breaks the sequence of consecutive letters. Thus CDE does not align with the ordered block structure.

Option D:
Option D, AZB, does not represent the next three consecutive letters after A. It changes the internal order instead of continuing to B, C and D. Consequently, AZB fails to reflect the stepwise nature of the series.

The starting letters are Z, W, T and Q, which stand at positions 26, 23, 20 and 17, decreasing by 3 each time. Each group consists of three consecutive letters in forward alphabetical order. Continuing this rule, the next starting position is 14, corresponding to N, and the next two letters are O and P. Therefore NOP is the only group that respects both the minus three jump and the consecutive letter structure.

Option A:
Option A, OPQ, starts with O at position 15, which is only two positions below Q rather than three. This breaks the consistent backward step of three positions in the starting letters. Although OPQ is internally consecutive, it does not come from the governing position rule, so it is not correct.

Option B:
Option B, RST, moves forward from Q instead of backward, reversing the direction of the pattern. The sequence clearly shows the starting letters moving left in the alphabet by three positions. Because RST represents a forward move, it contradicts this behaviour.

Option C:
Option C, KLM, begins at K, which is position 11, giving a backward jump of 6 from Q rather than 3. This doubles the step size unexpectedly and disrupts the regular decrement. As the series does not indicate any change in the size of the backward jump, KLM cannot be accepted.

Option D:
Option D is correct because N lies exactly three positions before Q and NOP forms a block of three consecutive letters. It preserves both the direction and magnitude of the movement in the first letter, and maintains the same internal structure of the groups. This makes NOP the valid continuation of the letter group series.

The groups descend in blocks of three letters: XYZ (24–26), UVW (21–23), RST (18–20) and OPQ (15–17). Each starting letter reduces by 3 positions (24, 21, 18, 15). The next starting position should be 12, corresponding to L, and the next block is LMN (12–14). Hence LMN is the only group that continues the pattern of moving each block three letters earlier in the alphabet.

Option A:
Option A, LMN, is correct because it begins at L, which is 3 letters before O, and forms the next three-letter block in descending order. It respects the length of the groups and the step size of −3 for the starting letter. This makes LMN a perfect fit for the series.

Option B:
Option B, KLM, starts too early at K, corresponding to a step of −4 from O, not −3. This over-adjustment does not match the observed behaviour of the series. As such, KLM cannot be considered correct.

Option C:
Option C, NOP, reverses the direction by moving forward after OPQ instead of backward. It also overlaps with OPQ by reusing O and P in a way that contradicts the blockwise descent. Therefore NOP does not align with the series rule.

Option D:
Option D, MNO, starts at M, which is 2 letters before O, not 3 letters before O. It breaks the fixed interval between the initial letters of successive blocks. Because it ignores the −3 step pattern, MNO is not a valid continuation.

The starting letters Q, N, K and H occupy positions 17, 14, 11 and 8, decreasing by 3 each time. Each group is a three letter block of consecutive letters in forward order. Continuing this pattern, the next starting letter is position 5, which is E, and the following letters are F and G, giving EFG. Therefore EFG fits both the minus three jump and the internal structure of the groups.

Option A:
Option A is correct because E lies exactly three positions before H and EFG continues with F and G as consecutive letters. It maintains the constant decrement in the starting letters and keeps the groups consistently formed. This alignment with both the numerical and structural aspects of the pattern makes EFG the correct answer.

Option B:
Option B, GHI, moves forward from H instead of backward, reversing the direction of the starting sequence. The series clearly shows the starting letters descending through the alphabet. As GHI would be a forward step, it does not conform to the observed rule.

Option C:
Option C, IJK, begins at I, which is only one position after H and also goes in the wrong direction. It neither preserves the backward movement nor maintains the required step size of three. Consequently, IJK cannot be the next term.

Option D:
Option D, ABC, starts at A, which is position 1, representing a jump of seven positions backward from H instead of three. This change in step size is not supported by any previous transition. As a result, ABC does not fit the pattern.