UGC NET Questions (Paper – 1)

The positions of these letters are Z(26), W(23), T(20), Q(17) and N(14). The difference between consecutive terms is −3 each time (26→23, 23→20, 20→17, 17→14). Continuing the same rule, the next position is 14 − 3 = 11, which is the letter K. Therefore K is the unique letter that preserves the constant backward step of 3.

Option A:
Option A, L, is at position 12, which is only 2 steps behind N at 14. This contradicts the strict pattern of subtracting 3 from the position each time. Because L does not maintain the consistent decrement, it cannot be part of the series.

Option B:
Option B, M, corresponds to position 13, giving a difference of 1 from N. There is no indication that the size of the backward step is reducing as the series progresses. Since the pattern clearly shows a constant −3, M fails to fit the rule.

Option C:
Option C, J, is at position 10, which is 4 positions behind N. This would increase the backward jump to −4, altering the original rule of the sequence. As there is no evidence of changing step sizes, J does not correctly continue the series.

Option D:
Option D is correct because K is at position 11, exactly 3 positions before N. This maintains the uniform backward movement that characterises the sequence. Keeping the decrement constant is essential for logical consistency, so K is the only valid next term.

The positions of the letters are B(2), F(6), J(10), N(14) and R(18). Each term increases by 4 positions (2→6, 6→10, 10→14, 14→18). Continuing this rule, the next position is 18 + 4 = 22, which corresponds to the letter V. Thus V is the only option that maintains the constant step size of 4 in the sequence.

Option A:
Option A, T, corresponds to position 20, which is only 2 steps ahead of R at 18. This contradicts the observed increment of 4 positions between consecutive terms. Because it does not respect the uniform difference, T cannot be the correct continuation.

Option B:
Option B, U, stands at position 21, giving a difference of 3 from R. The sequence does not display variable increments; it keeps a consistent jump of 4. Since U does not satisfy this constant difference property, it fails to fit the pattern.

Option C:
Option C is correct because V is at position 22, exactly 4 places after 18. This preserves the arithmetic progression of positions and ensures that the series continues smoothly. Any deviation from this step size would change the core structure of the series, so V is the only valid next term.

Option D:
Option D, W, lies at position 23, which is 5 steps beyond R. This would increase the gap toward the end of the series without any indication of such change earlier. The absence of a growing difference in previous steps means W cannot be justified by the pattern.

The positions of the letters are Z(26), X(24), U(21) and Q(17). The decreases between them are −2, −3 and −4, which form an increasing sequence of negative steps in magnitude. The next step should be −5, giving 17 − 5 = 12, which is the letter L. Hence L uniquely satisfies the pattern of successively larger backward jumps.

Option A:
Option A, O, lies at position 15, which would give a decrease of only 2 from Q. This contradicts the trend of increasing the size of the backward step. Since the differences must grow by 1 each time, O cannot fit the rule.

Option B:
Option B, N, is at position 14, implying a decrease of 3 from 17. This repeats a previous step size instead of extending it to −5. Therefore N does not reflect the evolving pattern of differences.

Option C:
Option C, K, corresponds to position 11, giving a drop of 6 from Q. This overextends the next decrement beyond what the sequence suggests. Because the model clearly shows steps of −2, −3, −4, then −5, moving to −6 breaks the logic.

Option D:
Option D is correct because L, at position 12, produces the required decrease of 5 from 17. It aligns with the systematic growth of the backward interval. By respecting the exact structure of the differences, L is the only consistent next term.