When two fair coins are tossed, the sample space consists of four equally likely outcomes: HH, HT, TH and TT. Exactly one head occurs in the outcomes HT and TH, giving 2 favourable cases. Therefore, the probability of exactly one head is 2/4, which simplifies to 1/2. Thus, 1/2 is the correct probability.
Option A:
A probability of 1/4 would correspond to just one favourable outcome out of four, but in this experiment there are two sequences that show exactly one head. Hence, 1/4 undercounts the favourable cases and is incorrect.
Option B:
1/2 is correct because the two favourable outcomes HT and TH out of four total outcomes give 2/4, which reduces to 1/2. This demonstrates a straightforward application of the probability formula for equally likely outcomes. Understanding such simple models helps in solving more advanced probability questions.
Option C:
3/4 would mean that three out of four outcomes have exactly one head, which is not true here. In reality, only two outcomes satisfy this condition, while HH and TT do not. Therefore, 3/4 exaggerates the likelihood and cannot be right.
Option D:
1/3 suggests an assumption of three equally likely outcomes, only one of which is favourable, which does not match the actual sample space of four outcomes. Thus, 1/3 is not compatible with the correct analysis of this experiment.
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