Using the simple interest formula I = PRT/100, we substitute I = 600, R = 10 and T = 3 to get 600 = P × 10 × 3 / 100. This simplifies to 600 = 0.3P, so P = 600 ÷ 0.3 = 2000. Therefore, the principal amount on which interest is calculated is ₹2000.
Option A:
If the principal were ₹1500, then the interest at 10% per annum for 3 years would be 1500 × 10 × 3 / 100 = ₹450, which is less than the given interest of ₹600. Hence, this value does not satisfy the data in the problem.
Option B:
If the principal were ₹1800, simple interest at the given rate and time would be 1800 × 10 × 3 / 100 = ₹540. This again does not match the stated interest of ₹600, so this option is not correct.
Option C:
A principal of ₹2000 is correct because it produces the exact interest mentioned: 2000 × 10 × 3 / 100 = ₹600. This agreement confirms that ₹2000 is the initial amount invested or borrowed. In aptitude questions, carefully rearranging formulas like this is a common requirement.
Option D:
If the principal were ₹2200, the interest would be 2200 × 10 × 3 / 100 = ₹660, which exceeds the given value. This shows that ₹2200 cannot be the starting amount for this problem. Therefore, this option must be rejected.
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