UGC NET Questions (Paper – 1)

Each term is a 5-letter consecutive block. Starting letters A(1), F(6), K(11), P(16) increase by +5. Next start is U(21), giving UVWXY.

Option A:
Option A starts at S(19), which is +3 from P, not +5.

Option B:
Option B is correct because U is +5 from P and V,W,X,Y follow consecutively.

Option C:
Option C starts at V(22), which is +6 from P, not +5.

Option D:
Option D repeats an earlier term.

Lengths increase 2,3,4,5 so next length is 6. Starting letters A(1), C(3), F(6), J(10) have gaps +2,+3,+4 so next gap is +5 → O(15). Six consecutive letters from O are OPQRST.

Option A:
Option A starts at L, not O, so it fails the starting-letter rule.

Option B:
Option B starts at M, not O, so it fails the starting-letter rule.

Option C:
Option C is correct because it starts at O and has exactly 6 consecutive letters.

Option D:
Option D starts at Q, not O, so it skips the required start.

Each group is a block of four consecutive letters. The starting letters are E, G, I and K (positions 5, 7, 9, 11), increasing by 2 each time. The next start is M (13), giving MNOP.

Option A:
Option A is correct because it begins at M, exactly two positions after K, and continues with N, O and P consecutively.

Option B:
Option B starts at N (14), which is +3 from K, not +2, so it breaks the step.

Option C:
Option C starts at L (12), only +1 from K, so it breaks the step.

Option D:
Option D starts at O (15), +4 from K, so it breaks the step.

The groups are four letter consecutive blocks where the starting letters J, L, N and P occupy positions 10, 12, 14 and 16, increasing by 2 each time. Each block then takes the next three letters in order. Continuing this rule, the next starting letter is position 18, which is R, and the block from R is RSTU. Thus RSTU uniquely keeps both the plus two starting step and the four letter structure.

Option A:
Option A, STUV, is a valid four letter block but begins at S, which is three steps after P instead of two. This changes the size of the jump in the starting letter, contradicting the constant increment of two. Therefore STUV does not align with the governing rule of the series.

Option B:
Option B, QRST, starts at Q, which is only one position after P. That reduces the step from two to one and breaks the arithmetic progression of starting positions. Because the pattern clearly shows a consistent plus two movement, QRST cannot be considered correct.

Option C:
Option C is correct because R is exactly two positions ahead of P and RSTU forms a proper four letter consecutive group. It extends the same even step difference in the starting letter and preserves the internal consecutiveness. This match with both structural aspects of the series makes RSTU the right answer.

Option D:
Option D, NOPQ, repeats an earlier block instead of moving forward. The series never reuses a previous group, and each term has a strictly increasing starting letter. As a result, NOPQ cannot be the next term.

In this series, the first letters are A, E, I, M, which correspond to positions 1, 5, 9 and 13, all increasing by 4. The second letters are D, H, L, P, i.e. positions 4, 8, 12 and 16, also increasing by 4. The next first letter after M (13) is Q (17) and the next second letter after P (16) is T (20). Hence QT is the only pair that continues the uniform +4 progression in both positions.

Option A:
Option A, QS, provides the correct first letter Q but gives S as the second letter, which is only 3 steps ahead of P. The series demands a constant increase of 4 positions for the second letter as well. Since S is inconsistent with the established step size, this option disrupts the pattern and is therefore incorrect.

Option B:
Option B is correct because Q and T are exactly 4 positions ahead of M and P respectively. This keeps the uniform step size intact for both components of the pair. By preserving the same arithmetic structure as in all previous terms, QT is the only option that maintains strict logical continuity in the series.

Option C:
Option C, QU, pushes the second letter forward to U, which is 5 positions after P. This overshoots the fixed increment and changes the rule mid-series. Since the first and second letters must follow the same step of +4, QU cannot be considered a valid continuation.

Option D:
Option D, QV, again uses the correct first letter Q but moves the second letter to V, which is 6 positions ahead of P. This introduces a larger increment than used before, breaking the constant-difference pattern that defines the sequence. Therefore option D does not fit the series.

The starting letters of the groups are B, E, H and K, which occupy positions 2, 5, 8 and 11 in the alphabet, increasing by 3 each time. The groups themselves are made of three consecutive letters in forward order. Continuing the same rule, the next starting letter is position 14, which is N, and the consecutive letters after N are O and P. Therefore NOP is the only group that fits both the plus three jump in the starting letter and the three letter consecutive structure.

Option A:
Option A is correct because it begins with N, exactly three positions after K, and continues with O and P to form a consecutive three letter block. It preserves the constant increase of three positions in the first letter across all terms. It also maintains the same internal structure where each group is made of adjacent letters in correct order. These two properties together make NOP the valid continuation.

Option B:
Option B, MNO, starts at M, which is only two positions after K, so it breaks the fixed jump of three positions for the starting letters. Although MNO is itself a set of three consecutive letters, it does not arise from the same position rule used earlier. Because it violates the numerical pattern in the first letter, it cannot be the correct next term.

Option C:
Option C, OPQ, begins at O, which is four positions after K and overshoots the required step. This makes the gap between KLM and OPQ larger than all previous jumps. Since the series shows a stable plus three increment, the excessive jump in the starting letter makes OPQ inconsistent with the pattern.

Option D:
Option D, LMN, uses L as the starting letter, but L was already part of the previous group KLM and does not follow the plus three progression from K. It would make the sequence repeat an internal letter instead of moving to the next scheduled starting point. Therefore LMN fails to continue the series logically.