UGC NET Questions (Paper – 1)

Statements A, B and C summarise the leap-year rule of the Gregorian calendar correctly. A states the basic rule for ordinary years divisible by 4 but not by 100. B adds the exception that years divisible by 400 are leap years even though they are century years. C notes that a century year divisible by 100 but not by 400 is not a leap year. E is also true because 366 days equal 52 weeks plus 2 days, giving two odd days. D is false since divisibility by 8 alone does not override the 100 and 400 year conditions, so A, B, C and E only are correct.

Option A:
Option A is incomplete because it omits E and thus does not connect leap years to the concept of odd days, which is often used in calendar-based reasoning questions. Without E, the relationship to day-of-week changes is not fully explained.

Option B:
Option B is also incomplete since it includes only B, C and E and omits A, failing to mention the basic divisibility-by-4 rule for non-century years. This makes the description of leap-year identification partial.

Option C:
Option C is correct because it collects all true statements, including the ordinary rule, the century-year modification and the odd-day implication, while rejecting D, which overgeneralises divisibility by 8. It reflects the treatment of leap years in NET calendar problems.

Option D:
Option D is incorrect as it introduces D, which asserts that every year divisible by 8 is leap, even though century exceptions contradict this, and it omits B. The combination therefore contains an error and cannot be considered correct.

Statements A and B correctly describe the length of non-leap and leap years and the divisibility rule used to identify leap years. Statement C is true because the weekly cycle repeats every 7 days, and E is also correct as calendar questions usually count odd days from a known reference day. Statement D is false because odd days are calculated modulo 7, not modulo 5. Therefore, the combination A, B, C and E only is correct.

Option A:
Option A is incomplete because it omits E and therefore misses the practical step of accumulating odd days from a reference, which is crucial for solving day-of-week problems. Without E, the method is not fully described.

Option B:
Option B is wrong as it includes D, which uses modulo 5 instead of modulo 7, and so miscalculates odd days. This incorrect rule makes the entire option unacceptable.

Option C:
Option C is incomplete since it leaves out A and B, thereby not explicitly stating the year-length facts and leap-year rule, even though it contains two true statements.

Option D:
Option D is correct because it gathers all the true statements and excludes D, the incorrect modulus rule, giving a complete and accurate picture of odd-day calculations in calendar questions.