UGC NET Questions (Paper – 1)

Each term shifts every letter by +2: ACEG→CEGI→EGIK→GIKM. Next is GIKM shifted by +2 to IKMO.

Option A:
Option A is correct because it applies the same +2 shift to each letter and keeps the +2 internal spacing.

Option B:
Option B does not come from adding +2 to each letter of GIKM.

Option C:
Option C breaks the internal spacing because M→N is +1.

Option D:
Option D starts with J instead of I, so it is not the +2 shift continuation.

Every group contains five letters, each separated by two positions from the next. From one group to the next, each letter shifts forward by one place: ACEGI becomes BDFHJ, then CEGIK, then DFHJL. Applying this shift again, D, F, H, J and L become E, G, I, K and M respectively. Hence EGIKM is the only group that continues the pattern.

Option A:
Option A, EGJLN, distorts the equal spacing and is not formed by adding one to each letter in DFHJL. Therefore it does not respect the structural rule.

Option B:
Option B, EGIJL, breaks the regular spacing and is not obtained by a consistent +1 transformation of DFHJL.

Option C:
Option C is correct because it advances each letter of DFHJL by exactly one position while preserving the +2 spacing inside the group.

Option D:
Option D, FGIKM, starts with F instead of E, so it does not match the +1 shift from DFHJL.

Each group is made of five letters that are equally spaced from each other in the alphabet, forming a regular ladder pattern. ADGJM, BEHKN, CFILO and DGJMP all have the same internal step size between successive letters and each new group is obtained by moving all letters one position forward. Applying this simple shift to DGJMP gives E, H, K, N and Q. The resulting group EHKNQ preserves the internal spacing and extends the vertical sequences of every column, so it is the correct continuation.

Option A:
Option A, EHJMQ, uses some of the right letters but places them in positions that break the constant spacing between adjacent letters. The sequence from H to J to M to Q does not match the regular step pattern of the series. Because the internal distances are wrong, EHJMQ cannot be the answer.

Option B:
Option B, EIKNQ, changes the second letter so that the equal increments between letters inside the group are lost. It does not arise from a uniform one step shift of DGJMP. As a result, EIKNQ fails to fit the exact construction rule.

Option C:
Option C, FHKNR, starts with F instead of E and moves the letters in a way that does not preserve the ladder structure or the column wise progressions. The clear transformation from one group to the next is no longer visible. Therefore FHKNR is not a valid continuation.

Option D:
Option D is correct because EHKNQ is formed by adding one to each letter of DGJMP and it keeps the same step between neighbouring letters as in all previous groups. The vertical sequences remain intact in every column. This strict adherence to the series rule makes EHKNQ the only suitable next term.

Each group consists of four letters that are two positions apart inside the alphabet, for example ACEG uses positions 1, 3, 5 and 7. From one group to the next, every letter shifts one step forward: ACEG becomes BDFH, then CEGI, then DFHJ. Applying the same column wise +1 shift again, D becomes E, F becomes G, H becomes I and J becomes K, giving EGIK. Thus EGIK uniquely preserves the regular spacing and advancement.

Option A:
Option A, EFGH, destroys the spacing pattern because the letters are consecutive instead of being two steps apart. It does not arise from adding one to each letter of DFHJ. Since the series is defined by both even spacing and uniform shifting, EFGH does not fit the rule.

Option B:
Option B, EGIJ, starts correctly with E and G but changes the last two letters to I and J. The final letter J is only one step ahead of I instead of two steps ahead of G, breaking the uniform internal differences. Because it fails to keep both the +2 spacing and the consistent shift from DFHJ, EGIJ cannot be the correct answer.

Option C:
Option C, EGHJ, again loses the pattern of equal spacing. The letters E, G, H and J have mixed intervals, and this group is not produced by a simple +1 shift from DFHJ. Even though some letters look close to the expected ones, the underlying structure is not preserved.

Option D:
Option D is correct because E, G, I and K are each exactly one step ahead of D, F, H and J respectively. It keeps the difference of two positions between successive letters inside the group and maintains the same transformation that generated all earlier terms. Therefore EGIK is the logical next term in the series.