Let the original numbers be 7x and 4x. After subtracting 5 from each, they become 7x β 5 and 4x β 5, and their ratio is 3:1. Thus, (7x β 5)/(4x β 5) = 3/1. This gives 7x β 5 = 3(4x β 5) = 12x β 15, which simplifies to 10 = 5x and hence x = 2. Therefore, the original numbers are 14 and 8, and the larger is 14.
Option A:
Option A, 8, is the smaller of the two numbers in the correct solution. While it satisfies the original ratio when combined with 14, the question asks for the larger number. Choosing 8 would misinterpret which quantity the problem seeks.
Option B:
Option B is correct because 14 equals 7x with x = 2 and is the larger term in the ratio 7:4. Substituting 14 and 8 into the transformed condition, we get (14 β 5):(8 β 5) = 9:3 = 3:1, which exactly matches the new ratio, confirming that 14 is the correct larger original number.
Option C:
Option C, 16, would require the smaller number to be 16 Γ (4/7) β 9.14 to preserve the ratio 7:4. This is not an integer and, even if approximated, would not yield a new ratio of 3:1 after subtracting 5. Thus, 16 cannot be the larger number that fits all conditions.
Option D:
Option D, 18, similarly leads to a non-integer partner of 18 Γ (4/7) β 10.29 under the original ratio and fails to produce the required new ratio of 3:1 after the subtraction. Hence, 18 is inconsistent with the given information.
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