Distance is the product of speed and time. In 3 hours, the slower train at 40 km/h covers 40 Γ 3 = 120 km. The faster train at 60 km/h covers 60 Γ 3 = 180 km in the same time. The difference in distances is 180 β 120 = 60 km, so the faster train travels 60 km more than the slower one.
Option A:
Option A, 40 km, would be correct if the speed difference were 40 km/h for 1 hour, but here the speed difference is 20 km/h and the time is 3 hours.
Option B:
Option B, 50 km, has no direct basis in the given speeds and time and thus reflects an incorrect computation.
Option C:
Option C, 60 km, matches the product of the speed difference (60 β 40 = 20 km/h) and the common time of 3 hours. It properly accounts for how much farther the faster train travels in the same interval.
Option D:
Option D, 80 km, overstates the difference and would require either a larger gap in speed or a longer time interval.
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