UGC NET Questions (Paper – 1)

Consecutive terms differ by 4: 2 − (−2) = 4, 6 − 2 = 4 and 10 − 6 = 4. This shows an arithmetic progression with common difference 4. Adding 4 to the last term 10 gives 14. Therefore, 14 is the correct next term in the sequence.

Option A:
Option A is 12, which is only 2 more than 10 and does not match the consistent difference of 4. Using 12 would reduce the step size at the end without justification. Hence, it cannot be correct.

Option B:
Option B equals 14, obtained by 10 + 4, which continues the established rule perfectly. The full series −2, 2, 6, 10, 14 keeps the same constant increase each time. This makes 14 the only value that preserves the pattern.

Option C:
Option C is 16, giving a difference of 6 from 10. No such difference appears earlier in the series, so this new step would break the arithmetic structure. Therefore, 16 is not the correct continuation.

Option D:
Option D is 18, which would involve adding 8 to 10 and drastically changing the rate of increase. Since the series has shown only jumps of 4, this option contradicts that behaviour and must be rejected.

The positions of the letters are B(2), F(6), J(10), N(14) and R(18). Each term increases by 4 positions (2→6, 6→10, 10→14, 14→18). Continuing this rule, the next position is 18 + 4 = 22, which corresponds to the letter V. Thus V is the only option that maintains the constant step size of 4 in the sequence.

Option A:
Option A, T, corresponds to position 20, which is only 2 steps ahead of R at 18. This contradicts the observed increment of 4 positions between consecutive terms. Because it does not respect the uniform difference, T cannot be the correct continuation.

Option B:
Option B, U, stands at position 21, giving a difference of 3 from R. The sequence does not display variable increments; it keeps a consistent jump of 4. Since U does not satisfy this constant difference property, it fails to fit the pattern.

Option C:
Option C is correct because V is at position 22, exactly 4 places after 18. This preserves the arithmetic progression of positions and ensures that the series continues smoothly. Any deviation from this step size would change the core structure of the series, so V is the only valid next term.

Option D:
Option D, W, lies at position 23, which is 5 steps beyond R. This would increase the gap toward the end of the series without any indication of such change earlier. The absence of a growing difference in previous steps means W cannot be justified by the pattern.

The series consists of consecutive odd numbers, each 2 greater than the previous one. We see 11, 13, 15 and 17 with differences of 2 throughout. Adding 2 to 17 gives 19. Therefore, 19 is the next consecutive odd number and fits the pattern.

Option A:
Option A is 18, which is an even number and would break the sequence of odd integers. It also changes the difference from 2 to 1, so it cannot be correct.

Option B:
Option B is 20, another even number, and is 3 greater than 17. This disturbs both the parity and the constant difference. Thus, it does not maintain the pattern.

Option C:
Option C is 21, which is odd but lies 4 units above 17 rather than 2. That disrupts the simple increase by 2 seen in the earlier terms. Therefore, 21 is not appropriate.

Option D:
Option D equals 19, an odd number exactly 2 more than 17. The extended series 11, 13, 15, 17, 19 keeps the same difference and parity property. Hence, this option correctly continues the sequence.

The first letters are D(4), H(8), L(12) and P(16), each increasing by 4. The second letters are G(7), K(11), O(15) and S(19), again increasing by 4. Continuing this pattern, the next first letter is 16 + 4 = 20 (T) and the next second letter is 19 + 4 = 23 (W). Thus TW is the only pair that keeps the +4 increment intact for both positions.

Option A:
Option A, TW, is correct because it aligns perfectly with the constant step size applied to both letters. It places T as the next in the first-letter progression and W as the next in the second-letter progression. This combination preserves the arithmetic structure of the series.

Option B:
Option B, UX, shifts both letters further than necessary and changes the relative spacing between them. It does not correspond to the next set of positions obtained by adding 4. Because it breaks the consistent arithmetic progression, UX cannot be accepted.

Option C:
Option C, SV, uses S as the first letter, which should actually be the second letter based on previous terms. It also introduces a different spacing between the letters, disturbing the fixed difference of four positions for each component across terms. Hence SV does not satisfy the precise pattern.

Option D:
Option D, TV, gives the correct first letter T but moves the second letter only to V, which is position 22 instead of 23. This violates the required +4 movement in the second component. Since both positions must follow identical step sizes, TV cannot be the correct continuation.

The differences between consecutive terms are 3, 3, 3 and 3, so this is an arithmetic progression with common difference 3. To continue the series we must add 3 to the last term 16. Doing so gives 19 as the next term. This keeps the entire sequence consistent with the same constant difference rule. Therefore, 19 is the correct continuation.

Option A:
Option A fits the pattern because 16 + 3 = 19, preserving the constant difference of 3 seen in all earlier steps. The resulting sequence 4, 7, 10, 13, 16, 19 remains a perfect arithmetic progression. This makes the structure easy to verify in an exam setting. Hence, this option correctly follows the observed rule.

Option B:
Option B gives 18, which is only 2 more than 16 and breaks the fixed increment of 3. If 18 were chosen, the last difference would be 2 instead of 3, making the series inconsistent. Therefore, this value cannot be accepted as the correct next term.

Option C:
Option C gives 20, producing a last jump of 4 from 16 to 20. None of the earlier differences is 4, so this would introduce an unexplained change in the pattern. As competitive exams expect a single clear rule, this option must be rejected.

Option D:
Option D gives 21, which is 5 more than 16 and leads to a last difference of 5. This is even further from the established difference of 3 between earlier terms. Because it contradicts the uniform structure of the series, it cannot be the correct answer.

The sequence lists consecutive odd numbers starting from 1, with each term 2 greater than the previous one. We have 1, 3, 5, 7 and 9, all odd and evenly spaced. Adding 2 to 9 gives 11. Hence, 11 is the correct next term that keeps the list of odd numbers in order.

Option A:
Option A is 10, which is even and would break the pattern of odd integers. It also changes the difference from 2 to 1, so it does not match the structure.

Option B:
Option B equals 11, maintaining both the odd property and the consistent step of 2. Extending the series to 1, 3, 5, 7, 9, 11 keeps the progression uninterrupted. This makes 11 the appropriate continuation.

Option C:
Option C is 13, which is an odd number but lies 4 units above 9. Choosing 13 would skip 11 and alter the fixed difference of 2. Therefore, it cannot be the immediate next term.

Option D:
Option D is 15, which is further away and would correspond to a difference of 6 from 9. This would distort the regularity of the sequence. So, 15 is not correct in this context.

Consecutive terms differ by 7: 11 − 4 = 7, 18 − 11 = 7 and 25 − 18 = 7. This confirms an arithmetic progression with common difference 7. Adding 7 to the last term 25 gives 32. Therefore, 32 is the correct next term in the sequence.

Option A:
Option A is 29, which is only 4 greater than 25 and breaks the consistent step of 7. There is no reason in the earlier terms to reduce the difference. Hence, 29 is not correct.

Option B:
Option B equals 32, coming from 25 + 7 and preserving the constant difference of 7. The series 4, 11, 18, 25, 32 maintains a clear arithmetic structure. This makes 32 the appropriate continuation.

Option C:
Option C is 35, which is 10 more than 25 and introduces a difference of 10 not seen earlier. This would create an irregular jump at the end of the series. Therefore, 35 does not match the pattern.

Option D:
Option D is 36, giving a final difference of 11. Such a difference is unsupported by any prior step and distorts the simple structure. Thus, 36 is not the correct answer.

The series shows multiples of nine: 9×1, 9×2, 9×3 and 9×4. Following this, the next term should be 9×5. Computing 9×5 gives 45, so 45 is the correct extension of the sequence.

Option A:
Option A is 40, which is not divisible by 9 and does not follow the multiplication rule. Including 40 would disrupt the pattern of multiples of nine. Therefore, it is not correct.

Option B:
Option B is 44, which again is not a multiple of 9 and lies just below 45. It has no direct connection with the established series. Hence, it does not fit the rule.

Option C:
Option C is 48, which equals 9×5 + 3 and is not a pure multiple of nine here. The pattern has not used any additional constant, so 48 cannot be accepted.

Option D:
Option D equals 45 and follows naturally as 9×5. The full sequence 9, 18, 27, 36, 45 keeps the same multiplication by 9 relationship. This makes 45 the valid next term.

Each term is 5 more than the previous one, so the series is an arithmetic progression with common difference 5. We have 5, 10, 15 and 20 by repeatedly adding 5. Adding 5 to 20 gives 25. Therefore, 25 is the correct next term in the sequence.

Option A:
Option A preserves the pattern because 20 + 5 = 25 continues the same step used throughout. The extended series 5, 10, 15, 20, 25 remains a clean list of multiples of five. This makes the logic straightforward and exam friendly.

Option B:
Option B is 24, which is only 4 more than 20 and would change the common difference from 5 to 4. That alteration is not supported by any evidence in the earlier terms. Hence, this option is not consistent with the rule.

Option C:
Option C is 30, which would require a jump of 10 from 20 to 30, whereas all earlier jumps were 5. Introducing a larger difference at the end breaks the uniform progression. Therefore, 30 is not the correct answer.

Option D:
Option D is 22, giving a difference of 2 from 20 and severely disrupting the pattern of adding 5 each time. Such an abrupt change contradicts the clear structure of the series. Thus, this option must be rejected.

The series consists of consecutive even numbers increasing by 2 each time. We move from 2 to 4, 4 to 6, 6 to 8 and 8 to 10, always adding 2. Adding 2 to 10 gives 12. Therefore, 12 is the correct next term in the sequence.

Option A:
Option A is 11, which is odd and does not fit a series of even numbers. It also breaks the uniform difference of 2. Hence, this option is not appropriate.

Option B:
Option B is 14, which is even but is 4 more than 10. That would skip 12 and change the fixed increment of 2. Thus, it cannot be the immediate next term.

Option C:
Option C equals 12 and maintains both the even nature and the step size of 2. The extended series 2, 4, 6, 8, 10, 12 remains a clean list of consecutive even integers. This makes 12 the correct answer.

Option D:
Option D is 16, which is 6 more than 10 and leaves out 12 and 14. That jump is inconsistent with the pattern of adding 2, so 16 cannot be chosen here.