A’s one day work is 1/10 of the job and B’s one day work is 1/15 of the job. When they work together, the daily work done is the sum of their individual rates: 1/10 + 1/15. Taking the LCM of 10 and 15 gives 30, so the combined rate is (3/30 + 2/30) = 5/30 = 1/6. Thus, together they complete 1/6 of the work each day and need 6 days to finish the entire work.
Option A:
Option A, 4 days, would imply a combined rate of 1/4 per day, which is higher than what A and B can achieve together. The actual sum of their rates does not support completion in 4 days.
Option B:
Option B, 5 days, would mean they do 1/5 of the work per day, requiring a combined rate larger than 1/6. However, the calculated total rate from their individual capacities is only 1/6.
Option C:
Option C is consistent with the reciprocal method: adding 1/10 and 1/15 gives 1/6, whose reciprocal is 6 days. This uses the standard approach for time and work problems and fits the given data exactly.
Option D:
Option D, 8 days, underestimates their combined productivity and corresponds to a rate of 1/8 per day, which is lower than the actual 1/6 per day.
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