UGC NET Questions (Paper – 1)

Every group is a five letter palindrome where the first and last letters match, and the second and fourth letters also match. Moving from one term to the next, all letters shift one step forward in the alphabet: ABCBA becomes BCDCB, then CDEDC, then DEFED. Continuing this rule, D becomes E, E becomes F and F becomes G for the central letter, so the new group must be EFGFE. This preserves both the palindromic structure and the uniform forward movement.

Option A:
Option A is correct because it uses E as the new outer letter, F as the new second and fourth letters and G as the new centre. These letters are each obtained by shifting the corresponding letters of DEFED forward by one position. The result is a perfect five letter palindrome that mirrors the behaviour of the earlier terms.

Option B:
Option B, EFHFE, introduces H as the central letter while the second and fourth letters remain F. That would mean the centre has moved two steps from E to H instead of one, breaking the consistent +1 progression. Since the pattern does not show unequal jumps, EFHFE cannot be the correct continuation.

Option C:
Option C, EFGGF, loses the palindromic form because the first and last letters are not the same. The series clearly maintains symmetry in every term. By changing the structure of the word, EFGGF fails to fit the given pattern.

Option D:
Option D, EFFGE, also spoils the required symmetry and does not match the simple column wise shift from DEFED. The positions of letters are altered in a way that is not supported by any earlier step. Therefore EFFGE cannot be accepted as the next term.