Decimal from binary 1111011 – UGC NET Question

1111011₂ = 64 + 32 + 16 + 8 + 0 + 2 + 1 = 123.

Option A:
Option A correctly sums the weights of all set bits to 123.

Option B:
Option B is too small and would require fewer set bits.

Option C:
Option C is too large and implies an extra contribution.

Option D:
Option D is also inconsistent with the correct sum.