Five letter series with wide equal gaps – UGC NET Question

Every term contains five letters spaced in the same wide way across the alphabet, and each new group is obtained by shifting all letters one step forward. AFKPU becomes BGLQV, then CHMRW, then DINSX through this uniform motion in every column. To continue, we add one to each letter of DINSX: D becomes E, I becomes J, N becomes O, S becomes T and X becomes Y, giving EJOTY. Since EJOTY alone preserves both the internal spacing and the simple column wise shift, it is the correct next term.

Option A:
Option A, EJOSY, changes the last two letters so that the distances inside the group no longer match those of the earlier terms. The relationship among O, S and Y differs from the regular jumps seen in AFKPU, BGLQV, CHMRW and DINSX. Because the spacing is inconsistent, EJOSY cannot correctly continue the series.

Option B:
Option B, FKPUZ, begins with F instead of E, so the starting letter jumps two steps ahead rather than one after D. It also alters the internal distances towards the end of the group. This disruption of both starting position and spacing shows that FKPUZ is not in line with the pattern.

Option C:
Option C, EKNQY, mixes some correct letters with others that do not arise from a one step shift of DINSX. The middle letters do not follow the same vertical sequences present in earlier groups. Therefore EKNQY fails to maintain the strict mechanical rule behind the series.

Option D:
Option D is correct because EJOTY results from applying the identical transformation that links each pair of consecutive terms in the series. It keeps the same distance between each pair of adjacent letters and fits neatly after DINSX in every column. This full consistency with the observed construction confirms EJOTY as the intended continuation.