Four-letter blocks descending by three – UGC NET Question

The starting letters W, T, Q and N occupy positions 23, 20, 17 and 14, decreasing by 3 each time. Each term after the starting letter gives the next three consecutive letters. Continuing this rule, the next starting letter is position 11, which is K, and the block from K is KLMN. Thus KLMN preserves both the minus three jump and the four letter consecutive structure.

Option A:
Option A is correct because K is exactly three positions before N, and the letters L, M and N follow consecutively. It continues the steady backward movement of the starting letters and keeps each group a simple sequence of four adjacent letters. This is fully consistent with the pattern in the given series.

Option B:
Option B, LMNO, starts at L, which is only two positions before N, and therefore changes the step size from minus three to minus two. This inconsistency in the backward jump breaks the arithmetic pattern underpinning the sequence. As a result, LMNO cannot be the correct next term.

Option C:
Option C, PQRS, goes forward from N instead of backward, reversing the direction of the starting letters. The series does not exhibit any forward jumps in its current segment, so PQRS does not align with the logic of the pattern.

Option D:
Option D, UVWX, also represents a forward jump, returning to letters that appeared earlier in the extended alphabetic ordering. It fails to continue the recorded progression of starting letters moving leftward by three positions. Hence UVWX is not a valid continuation.