This series is generated by the rule โmultiply the previous term by 3 and add 2โ. We have 1ร3+2 = 5, 5ร3+2 = 17, 17ร3+2 = 53 and 53ร3+2 = 161. Applying the same rule to 161 gives 161ร3+2 = 483+2 = 485. Hence 485 is the only value that continues the sequence in strict accordance with the recursive pattern.
Option A:
Option A gives 479, which cannot be written as 161ร3+2 and would require subtracting an additional amount. This contradicts the consistently โ+2โ adjustment after multiplication by 3 in the earlier steps. Therefore 479 is not consistent with the rule.
Option B:
Option B gives 481, corresponding to 161ร3โ2, which would change the sign of the constant adjustment and break the established behaviour. Thus 481 is not a valid continuation of the series.
Option C:
Option C gives 483, equal to 161ร3, but this omits the โ+2โ that appears in every transition. This makes the rule incomplete for the last step, so 483 cannot be accepted as correct.
Option D:
Option D gives 485, exactly equal to 161ร3+2. It maintains the same transformation applied in all earlier steps, keeping the pattern transparent and stable. Consequently, 485 is the correct next term in the series.
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