From the first statement, we know that every square belongs to the set of rectangles. The second statement says that no rectangles belong to the set of circles, so the sets of rectangles and circles are disjoint. Since squares are a subset of rectangles, and rectangles do not overlap with circles, squares also cannot overlap with circles. Therefore, the conclusion that no squares are circles is logically valid.
Option A:
Option A, βSome squares are circles,β contradicts the second premise. If any square were also a circle, it would simultaneously be a rectangle and a circle, which is impossible when no rectangles are circles.
Option B:
Option B, βNo squares are circles,β correctly applies the idea that if rectangles and circles are disjoint sets, then any subset of rectangles (such as squares) must also be disjoint from circles. Hence, no square can be a circle.
Option C:
Option C, βAll circles are squares,β reverses and overextends the relationship. We are told only that all squares are rectangles, not that all circles are contained in the set of squares.
Option D:
Option D, βSome rectangles are circles,β is directly inconsistent with the second statement, which asserts that no rectangles are circles.
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