UGCNET Questions

The days of the week repeat in a cycle of 7. To find the day after 10 days from Monday, we compute 10 modulo 7, which gives a remainder of 3. This means the day will be 3 days ahead of Monday. Counting forward, Monday plus 3 days is Thursday. Thus, after 10 days, it will be Thursday.

Option A:
Option A, Wednesday, is only 2 days ahead of Monday and would correspond to a remainder of 2, not 3, when dividing the number of days by 7.

Option B:
Option B aligns the remainder of 3 with a three-day forward move from Monday, giving Thursday. It uses the cyclic nature of the week correctly and therefore identifies the correct resulting day.

Option C:
Option C, Friday, is 4 days ahead and would correspond to a remainder of 4, which is not obtained when dividing 10 by 7.

Option D:
Option D, Sunday, is 6 days after Monday and would match a remainder of 6, not the remainder of 3 that arises here.

The days of the week repeat every 7 days. We find the effective shift by computing 50 mod 7. Since 50 = 7 × 7 + 1, the remainder is 1, meaning the day moves forward by 1 from Wednesday. One day after Wednesday is Thursday, so 50 days from now it will be Thursday.

Option A:
Option A, Thursday, is exactly one day after Wednesday and corresponds to a remainder of 1 in the modulo-7 calculation, so it matches the correct reasoning.

Option B:
Option B, Saturday, is three days after Wednesday and would be correct only if the remainder were 3, not 1.

Option C:
Option C, Sunday, is four days after Wednesday and would require a remainder of 4, which does not arise from 50 ÷ 7.

Option D:
Option D, Monday, is five days after Wednesday, again inconsistent with the actual remainder of 1.